获取具有重叠场景的日期持续时间的周数

Question

我需要计算员工的总分配周数和总替补周数。

员工在某个时间段内被分配到不同的项目中，该时间段总是从星期一开始，总是在星期五结束。 周一至周五将被视为 1 周。任何项目的持续时间都不能超过 2 周。 应调整分配状态的任何重叠周。 如果分配了员工身份并且该持续时间与任何替补周持续时间重叠或下降，则根本不应计算替补状态的该周持续时间。

下面是相关的场景如下。

"AssignedHistory":[ 
   {"Project":1,"status":"Assigned","Startdate":"01/03/2022", "Enddate":"01/07/2022" }, 
   {"Project":2,"status":"Assigned","Startdate":"01/10/2022", "Enddate":"01/14/2022" }, 
   {"Project":3,"status":"Assigned", "Startdate":"01/10/2022", "Enddate":"01/21/2022" },
   {"Project":4,"status":"Assigned", "Startdate":"02/21/2022", "Enddate":"02/25/2022" },       
   {"Project":5,"status":"Bench","Startdate":"01/17/2022", "Enddate":"01/21/2022" },
   {"Project":6,"status":"Bench","Startdate":"02/07/2022", "Enddate":"02/11/2022" }
   {"Project":7,"status":"Bench","Startdate":"02/21/2022", "Enddate":"03/04/2022" }    
]

在这里，我需要找到员工的总分配周数和总替补周数，预期结果应该是：

Total assigned week:4
Total benched week :1



     Since 1 week of assigned status is overlapping for 2 projects(no2 and no 3) from 10th Jan to 14 Jan so project 2 and 3 together will be counted as 2 .Also for assigned week of  project 3  it is overlapping with  benched week of  project 5  from 17th Jan to 21st Jan so in that case bench week for project 5 will be counted as 0.Similarly for assigned week of project 4,duration from 21st feb to 25th feb is overlapping or falls under benched week of  project 7 so in this case project 7 will be counted as 0.So only we have project 6 for benched week which doest not overlaps with any of the assined project duration.

这就是为什么总替补人数将是 1。

这就是我的想法。

 var assignedweek = AssignedHistory.Where(x => new []{"Assigned"}.Contains(x.status)).ToList();
    var benchedweek = AssignedHistory.Where(x => new []{"Bench"}.Contains(x.status)).ToList();
     
    List<DateTime> AssignedWeeklist = assignedweek
        .SelectMany(a => {
            DateTime firstSunday = a.Startdate.AddDays(-(int)a.Startdate.DayOfWeek);
            DateTime lastSunday = a.Enddate.AddDays(-(int)a.Enddate.DayOfWeek); 
            int weeks = (lastSunday - firstSunday).Days / 7 + 1;
    
            // Enumerate one Sunday per week
            return Enumerable.Range(0, weeks).Select(i => firstSunday.AddDays(7 * i));
        })
        .Distinct()
        .ToList();
        
        List<DateTime> BenchWeeklist = benchedweek
        .SelectMany(a => {
            DateTime firstSunday = a.Startdate.AddDays(-(int)a.Startdate.DayOfWeek);
            DateTime lastSunday = a.Enddate.AddDays(-(int)a.Enddate.DayOfWeek); 
            int weeks = (lastSunday - firstSunday).Days / 7 + 1;
    
            // Enumerate one Sunday per week
            return Enumerable.Range(0, weeks).Select(i => firstSunday.AddDays(7 * i));
        })
        .Distinct()
        .ToList();
        
        int assignedweekcount = AssignedWeeklist.Count();
        int benchedweekcount = BenchWeeklist.Except(AssignedWeeklist).Count();

它给出了正确的分配周数，但是如果板凳周与指定周重叠，则给出不正确的板凳周数。 有什么办法可以做到这一点？

Answer 1

您必须在 benchweek 上更改计算的逻辑，您必须按项目保留星期日日期：

        List<List<DateTime>> BenchWeeklist = benchedweek
        .Select(a => {
            DateTime firstSunday = a.StartDate.AddDays(-(int)a.StartDate.DayOfWeek);
            DateTime lastSunday = a.EndDate.AddDays(-(int)a.EndDate.DayOfWeek);

        return new List<DateTime>() { firstSunday, lastSunday }.Distinct().ToList() ;
        })
        .Distinct()
        .ToList();

        int assignedweekcount = AssignedWeeklist.Count();
        var benchedweekcount = 0;

        foreach(var l in BenchWeeklist)
        {
            var found = false;
            foreach(var it in l)
            {
                if (AssignedWeeklist.Contains(it)) found = true;
            }
            if (!found) benchedweekcount++;
        }