计算器节点 JS

Question

我正在做一些 JS，我需要你们的帮助，对于这个计算器，我需要它不要关闭，但 go 回来并问同样的问题，直到它得到正确的输入。 我知道我使用了 return calcInterface.close(); 它关闭的原因只是想看看它是否以这种方式工作。

//  import our package
           const readline = require("readline");

// Creating our interface

          const calcInterface = readline.createInterface({
          input: process.stdin,
          output: process.stdout,

    
});

          const validOperators = [
          "*",
          "-",
          "+",
          "/",
];

          calcInterface.question("What operation would you like to perform? ", 
          (operatorInput) => {
       if(!validOperators.includes(operatorInput)) {

        // Invalid operator
       console.log("That is not a valid operation, Please try again!");
        return calcInterface.close();
  }


          calcInterface.question("Please enter the first number ", (firstInput) => {
            const firstNumber = Number(firstInput);
            if(isNaN(firstNumber)) {

        // Invalid number
        console.log("This is not a number, Please try again!");
        return calcInterface.close();
    }


        calcInterface.question("Please enter the second number ", (secondInput) => {
            const secondNumber = Number(secondInput);
            if(isNaN(secondNumber)) {

                // Invalid number
                console.log("This is not a number, Please try again!", );
                return calcInterface.close();
            }

            const result = calculatorLogic(firstNumber, operatorInput, secondNumber);

            console.log(`Your Result Is: ${result}`);
            calcInterface.close();
        });
    });
});

       function calculatorLogic(firstNumber, operator, secondNumber) {
        if(operator === "+") return firstNumber + secondNumber;
        else if(operator === "-") return firstNumber - secondNumber;
        else if(operator === "*") return firstNumber * secondNumber;
        else if(operator === "/") return firstNumber / secondNumber;
}