Python 随机用户代理库错误<invalidheader: invalid return character or leading space in header: user-agent></invalidheader:>

Question

我一直在使用随机用户代理库为每个请求分配一个随机用户代理，

from random_user_agent.user_agent import UserAgent
from random_user_agent.params import SoftwareName, OperatingSystem


# you can also import SoftwareEngine, HardwareType, SoftwareType, Popularity from random_user_agent.params
# you can also set number of user agents required by providing `limit` as parameter

software_names = [SoftwareName.CHROME.value]
operating_systems = [OperatingSystem.WINDOWS.value, OperatingSystem.LINUX.value]   

user_agent_rotator = UserAgent(software_names=software_names, operating_systems=operating_systems, limit=100)

# Get list of user agents.
user_agents = user_agent_rotator.get_user_agents()

# Get Random User Agent String.
user_agent = user_agent_rotator.get_random_user_agent()


result = requests.get(url, headers={'User-Agent':f'{user_agent}'})

在发送请求时，我的用户代理看起来像这样：

\tMozilla/5.0 (Windows NT 6.3; WOW64) adbeat.com/policy AppleWebKit/537.36 (KHTML, like Gecko) Chrome/42.0.2311.90 Safari/537.36

\t 会导致我的请求失败并显示上述错误消息，这是库错误吗？

一种方法是在 user_agent 上使用 strip()

但我认为更有效的方法是在下面的步骤中指定只从那些以“Mozilla”开头然后是strip()的选项中进行选择？ 由于库可能包含错误的用户代理，我该如何实现呢？

user_agent = user_agent_rotator.get_random_user_agent()

所以这里指定 user_agent_rotator.get_random_user_agent() 只以 'Mozilla' 开头然后是 strip()？