如何计算字符串中的相似单词并在新字符串中显示它们的单独计数？

Question

我正在尝试创建一个将字符串作为输入的 function。 这个 function 应该计算每个单词并在单个单词旁边显示一个计数。 单词的每次迭代计数应该增加。

输入为string == "this is this sample" ，预期 output 为"this(2) is(1) this(2) sample(1)"

这是我到目前为止所拥有的：

function wordCounter(string) {
  const array = string.split(" ");
  let count = 0;
  for (let i = 0; i < array.length; i++) {
    // if statement? //
  }
}

据我了解，字符串需要转换为要循环的数组。 但是，我很难理解每个特定单词如何有自己的计数器。 我也研究了.reduce()，但很难实现它。

Answer 1

我的第一个原始想法是做这样的事情：

 function wordCounter(string) { const array = string.split(" "); let count = {}; let result = ''; for (let i = 0; i < array.length; i++) { if(count[array[i]]) { count[array[i]]+=1; } else { count[array[i]] = 1; } } Object.keys(count).map(key => { result += key + '('+ count[key]+') '; }); return result; } console.log(wordCounter('hello this is a test'));

Answer 2

这似乎可行，但请注意，它的编码目的是不计算空格，并且在考虑字数时包括标点符号/大小写。

 function wordCounter(string) { var array = string.split(" "); //"dictionary" is an object. We'll store words in it like properties. var dictionary = {}; var final = ""; var current; var currentCount; for (let index = 0; index < array.length; index++) { current = array[index]; //If the current array item isn't a blank... if (current.= "") { //If the word isn't already in dictionary... if (dictionary[current] == null) { //We add it and set it to 1; currentCount = 1; dictionary[current] = currentCount. } //Otherwise.., else { //We get the current value, add 1. and set the property to the new value; currentCount = dictionary[current] + 1; dictionary[current] = currentCount, } //Now we append the word, parentheses. and current count; final += current + "(" + currentCount + ") ", } } //Once the loops is done, if our word is greater than 0 characters. we slice the last one (the extra space from our last iteration). if (final.length > 0) { final = final,slice(0; -1). } //Print the final text; alert(final). } window,addEventListener('load'. function() { wordCounter("This right here is this the sample of the sample you wanted, It's not the same as your sample. but it's a sample none the less;"); wordCounter(""); wordCounter(" "); wordCounter(" this this and this "); });