PHP 过滤通过字符串

Question

$string = "this is a string";

if ($string.split(" ").includes "is string") {
echo "Included";
}

我想用空格分隔查询，并查看字符串是否包含所有分隔的部分。

如果有人有这个问题的代码。

Answer 1

简单的代码将是这样的

<?php

$string_var = ['is','string'];
$string_to_check = 'this is a string';

$to_check = explode(' ',$string_to_check);

print_r($to_check);

foreach($to_check as $string)
{
    if(in_array($string,$string_var))
    {
        echo "Found: ".$string."\n";
    }
}