Python - aiohttp API 响应内容是“StreamReader”类型而不是 JSON

Question

I'm learning the aiohttp library with Python 3.10 for making HTTP GET requests, and am practicing it with the GitHub v3 REST API. 这是我的基本请求代码：

# Python Standard Library imports
import asyncio
import sys

# External library imports
import aiohttp

# GitHub API v3 REST endpoint for licenses
GITHUB_URL: str = "https://api.github.com/licenses"
# GitHub query headers
GITHUB_HEADERS: dict = {
    "Accept": "application/vnd.github.v3+json"
}

async def main():

    async with aiohttp.ClientSession() as session:
        async with session.get(GITHUB_URL, headers = GITHUB_HEADERS) as GitHub_response:

            print(GitHub_response.content)

if __name__ == "__main__": 

    loop = asyncio.get_event_loop()
    loop.run_until_complete(main())

    sys.exit(0)

代码运行没有错误，但关键的print(GitHub_response.content行给了我：

<StreamReader 2037 字节 eof>

这不是我所期望的。 StreamReader object 到底是什么？

What I expected was the JSON output which the curl command curl -H "Accept: application/vnd.github.v3+json" "https://api.github.com/licenses would give me, which looks like:

[
  {
    "key": "agpl-3.0",
    "name": "GNU Affero General Public License v3.0",
    "spdx_id": "AGPL-3.0",
    "url": "https://api.github.com/licenses/agpl-3.0",
    "node_id": "MDc6TGljZW5zZTE="
  },
  {
    "key": "bsd-2-clause",
    "name": "BSD 2-Clause \"Simplified\" License",
    "spdx_id": "BSD-2-Clause",
    "url": "https://api.github.com/licenses/bsd-2-clause",
    "node_id": "MDc6TGljZW5zZTQ="
  },
.....

我尝试用print(GitHub_response.json())替换我的print()行，但这给了我：

<coroutine object ClientResponse.json at 0x7f7e452b5e00>

所以它仍然不是我期待的 JSON。

我做错了什么？ 以及如何修复我的 Python 代码，以便通过 aiohttp 获得实际的aiohttp响应？

谢谢你。

PS我尝试使用 Python requests库执行上述操作。 The content of the response in this case is a bytes object which I had to decode("utf8") first before using json.dumps() from the json library to turn it into actual JSON. 不确定这些信息是否有助于弄清楚我在使用aiohttp时搞砸了什么。

Answer 1

“内容”是StreamReader的一个实例。 这提供了一个 协程“读取”，它读取以字符串形式返回内容。 将以下示例插入您的代码中，您应该会得到预期的结果。

 x = await GitHub_response.content.read()
 print(x)