如何在嵌套列表理解中循环遍历字典？

Question

在下面的注释行中，我想遍历 v.prices （创建一个组合刻度），并且仍然能够在同一个嵌套列表理解中执行该循环时到达 k 和 obj 。 可能吗？ 还是我需要另一个列表才能在 python 中做到这一点？

from pprint import pprint

from typing import Generator

from datetime import datetime
from dataclasses import dataclass
from typing import Mapping


@dataclass(frozen=True)
class Tick:
    time: datetime
    prices: Mapping[str, float]


@dataclass(frozen=True)
class CombinedId:
    exchange: str
    instrument: str


@dataclass(frozen=True)
class CombinedTick:
    time: datetime
    prices: Mapping[CombinedId, float]


def combine2(ticks: Mapping[str, Generator[Tick, None, None]]) -> None:

    lis = sorted([CombinedTick(time=v.time, prices=[]) for _, v in ticks.items()], key=lambda d: d.time)
    m = [(k, v.prices, obj) for k, v in ticks.items() for obj in lis if obj.time == v.time]
    #m = [ (#LOOP THROUGH V.PRICES WHILE STILL ACCESSING K AND OBJ# k,v.prices,obj) for k,v in ticks.items() for obj in lis if obj.time == v.time]
    pprint(m)

abc = combine2(
    {'e1': Tick(time=datetime.now(), prices={'i1': 11.11, 'i2': 12.12, }),
     'e2': Tick(time=datetime.now(), prices={'i1': 13.13, 'i2': 14.14, }),
     'e3': Tick(time=datetime.now(), prices={'i1': 15.15, 'i2': 16.16, })}
)

Output: [[('e1',
   {'i1': 11.11, 'i2': 12.12},
   CombinedTick(time=datetime.datetime(2022, 2, 2, 2, 53, 5, 951433), prices=[]))],
 [('e2',
   {'i1': 13.13, 'i2': 14.14},
   CombinedTick(time=datetime.datetime(2022, 2, 2, 2, 53, 5, 951435), prices=[]))],
 [('e3',
   {'i1': 15.15, 'i2': 16.16},
   CombinedTick(time=datetime.datetime(2022, 2, 2, 2, 53, 5, 951437), prices=[]))]]
[('e1',
  {'i1': 11.11, 'i2': 12.12},
  CombinedTick(time=datetime.datetime(2022, 2, 2, 2, 55, 36, 242255), prices=[])),
 ('e2',
  {'i1': 13.13, 'i2': 14.14},
  CombinedTick(time=datetime.datetime(2022, 2, 2, 2, 55, 36, 242258), prices=[])),
 ('e3',
  {'i1': 15.15, 'i2': 16.16},
  CombinedTick(time=datetime.datetime(2022, 2, 2, 2, 55, 36, 242261), prices=[]))]