T-SQL：JSON 数组

Question

我查询 API 和 JSON output 我想保存到 Z9778840A01014B05C982Z 服务器表中。 下面是我如何模拟变换 JSON output：

当我运行这个：

DECLARE @J NVARCHAR(MAX) = '{"c":[4.935,4.935,4.9374,4.935,4.94],"t":[1643998980,1643999040,1643999100,1643999160,1643999220],"v":[1979,87494,9980,4382,17713]}';

SELECT [key] as jkey, value as c
FROM OPENJSON(@j, '$.c');

我明白了：

jkey,c
0,4.935
1,4.935
2,4.9374
3,4.935
4,4.94

但我希望这样：

jkey,c,t,v
0,4.935,1643998980,1979
1,4.935,1643999040,87494
2,4.9374,1643999100,9980
3,4.935,1643999160,4382
4,4.94,1643999220,17713

我花了几个小时，我无法弄清楚。 请帮忙。

Answer 1

只需加入其他键的键即可。

 DECLARE @J NVARCHAR(MAX) = '{"c":[4.935,4.935,4.9374,4.935,4.94],"t":[1643998980,1643999040,1643999100,1643999160,1643999220],"v":[1979,87494,9980,4382,17713]}'; SELECT c.[key] as jkey, c.value as c, t.value as t, v.value as v FROM OPENJSON(@j, '$.c') c LEFT JOIN OPENJSON(@j, '$.t') t ON t.[key] = c.[key] LEFT JOIN OPENJSON(@j, '$.v') v ON v.[key] = c.[key] ORDER BY jkey;

键	c	吨	v
0	4.935	1643998980	1979
1	4.935	1643999040	87494
2	4.9374	1643999100	9980
3	4.935	1643999160	4382
4	4.94	1643999220	17713

db<> 在这里摆弄