如何在句子中出现的单词的特定范围内查找单词是否存在于句子中

Question

如果存在另一个单词，我很困惑如何查找句子中是否存在某个单词。 让我举个例子，这样我想做的事情就变得更容易了？

现在我想标记一个字符串，其中“值”存在于“波动”的 5 个单词范围内，无论是向后还是向前。

因此，首先我们将搜索是否存在“波动”。 如果是，那么我们将在“波动”的 5 个单词范围内搜索“价值”。 根据这个逻辑，我将标记 sentence_1 和 sentence_2

sentence_1 = 'Value is the are he Fluctuate'      #Flagged Since 'value' is within 5-word range of 'fluctuate'
sentence_2 = "Value is the are she he" Not        #Not_Flagged since 'fluctuate' is not present
sentence_3 = "Fluctuate Value is the are she he"  #Flagged since the 'value' is within 5-word range of 'fluctuate'

谁能告诉我如何仅使用 python 或正则表达式将此逻辑应用于句子？

Answer 1

# does the sentence contain both words?
if 'value' in sentence and 'fluctuate' in sentence:
    value_positions = []
    fluctuate_positions = []

    # iterate over each word in the sentence and build two lists
    # of the positions where each word appears
    for position, word in enumerate(sentence.split()):
        if word == 'value':
            value_positions.append(position)
        elif word == 'fluctuate':
            fluctuate_positions.append(position)

    # iterate over the position lists
    for v in value_positions:
        for f in fluctuate_positions:
            if abs(v - f) <= 5:
                print('Yes') 

Answer 2

将句子拆分为一个列表，找到“Fluctuate”的索引并检查“Value”是否在找到的索引周围的子列表中：

i = -1
words = sentence.split()

while i < len(words):
    try:
        # find the index of the word, starting from the last index + 1 
        i = words.index("Fluctuate", i + 1)
    except ValueError:
        # index of "Fluctuate" not found
        break

    # slice a sublist with +/- 5 positions around i
    # and check if "Value" is in this sublist
    left = i - 5 if i - 5 > 0 else 0
    right = i + 6
    if "Value" in words[left:right]:
        print("flag")
        break