"如何从现有矩阵中获取新矩阵，但为新数组选择的元素在python中包含更多的元素？"

Question

嗨，我想从现有矩阵中获取另一个矩阵，但需要从随机生成的第一个数组中具有更多 1nes 的数字，这是我的第一个数组的代码。 我想继续循环，直到该行的所有数量为 11111111。我想生成连续具有更多数量的元素。

   import random


arr3 = []
arr4 = []
countOnesarr = [0]
totalones = 0
totalones2 = 0

for i in range(0, 8):
    countOnes = 0;
    for b in range(0, 8):
            arr2 = random.randint(0,1)
          
            if arr2>0.5:
                print(1, end=' ', sep = '')
            elif arr2<0.5:    
                print(0, end=' ', sep = '')
            else:
                print(arr2, end=' ', sep = '')
            countOnes=countOnes+arr2
            totalones = totalones + arr2

    print('Fitness: ', countOnes)
    arr3 += [countOnes]
    print()
print('Total Fitness: ', totalones)
print()
max_onesrow = max(arr3)

max_onesrowindex = arr3.index(max_onesrow)



for d in arr3:
    rolletewheelfit = d/totalones
    shorrolletewheel = round( rolletewheelfit, 2)
    arr4 += [shorrolletewheel]

max_value = max(arr4)

print('Max Fitness value: ',max_value)
max_index = arr4.index(max_value)
print()
print('index of the highest wheel share element most fittest', int(max_index))