如何跳过 postgresql 中特定 id 的行？

Question

我想要做的是只显示在生物和化学和计算机方面分别获得分数的 fk_students，例如 5 3 3，而不是 2，这在此处被视为失败，结果也得到了在科目中获得 2 分的学生。

*

select school_name,fk_students, count(marks),sum(marks) as total from students inner join remarks on fk_students = student_id
        inner join subjects on subject_id =  fk_subjects
        inner join school on school_id = fk_school_idd
        where marks = 3 or marks = 4 or marks = 5 
        group by fk_students,school_name
        except 
        select school_name,fk_students, count(marks),sum(marks) as total from students inner join remarks on fk_students = student_id
        inner join subjects on subject_id =  fk_subjects
        inner join school on school_id = fk_school_idd
        where marks =2 
        group by fk_students,school_name
        order by fk_students

不应显示包含 9 和 10 和 11 的列 fk_students，因为他们的科目有 2 分，这被认为是失败结果

Answer 1

我通过使用“在哪里”完整解决方案解决了这个问题，如下所示

select school_name,st_name,sum(marks) as total from students inner
join remarks on fk_students = student_id
inner join subjects on subject_id = fk_subjects
inner join school on school_id = fk_school_idd
group by fk_students,school_name,st_name
having sum(marks)=15
except
select school_name,st_name,sum(marks) as total from students inner
join remarks on fk_students = student_id
inner join subjects on subject_id = fk_subjects
inner join school on school_id = fk_school_idd
where fk_students = any(select fk_students from remarks
where marks in (2))
group by fk_students,school_name,st_name
having sum(marks)=15
order by school_name