为什么 Espresso 执行点击无法与 androidx AppCompatButton 一起使用？

Question

使用 Espresso 单击按钮时遇到问题，这是我的代码 xml 代码、测试代码和错误

<androidx.appcompat.widget.AppCompatButton
                    android:id="@+id/btn_create_account_register"
                    android:layout_width="248dp"
                    android:layout_height="41dp"
                    android:layout_gravity="center"
                    android:layout_marginTop="36dp"
                    android:background="@drawable/button_common"
                    android:text="@string/tv_buat_akun"
                    android:textAllCaps="true"
                    android:textColor="@color/white"
                    app:layout_constraintBottom_toBottomOf="parent"
                    app:layout_constraintEnd_toEndOf="parent"
                    app:layout_constraintStart_toStartOf="parent" />

然后，这是我的测试代码

fun ensureRegistrationForm() {
        onView(withId(R.id.btn_create_account)).check(matches(isDisplayed()))
        onView(withId(R.id.btn_create_account)).perform(click())
        onView(withId(R.id.tv_registration)).check(matches(withText(R.string.tv_registration)))
        onView(withId(R.id.btn_create_account_register)).check(matches(isDisplayed()))
        onView(withText(R.string.tv_buat_akun)).perform(click())

然后我得到错误，

androidx.test.espresso.PerformException: Error performing 'single click - At Coordinates: 515, 1585 and precision: 16, 16' on view 'an instance of android.widget.TextView and view.getText() equals string from resource id: <2131886299> [tv_buat_akun] value: Buat Akun'.
at androidx.test.espresso.PerformException$Builder.build(PerformException.java:1)
at androidx.test.espresso.base.DefaultFailureHandler.getUserFriendlyError(DefaultFailureHandler.java:9)
at androidx.test.espresso.base.DefaultFailureHandler.handle(DefaultFailureHandler.java:7)
at androidx.test.espresso.ViewInteraction.waitForAndHandleInteractionResults(ViewInteraction.java:8)
at androidx.test.espresso.ViewInteraction.desugaredPerform(ViewInteraction.java:11)
at androidx.test.espresso.ViewInteraction.perform(ViewInteraction.java:4)
at com.uad.thesis.plasmaconvalescent.RegistrationTest.ensureRegistrationForm(RegistrationTest.kt:54)
... 28 trimmed

任何人都可以帮忙吗？ 先感谢您

Answer 1

您已尝试使用字符串值访问您的按钮，但您需要使用 id 进行操作。 那么可以更新并尝试吗？

onView(withText(R.id.btn_create_account_register)).perform(click())