Azure Java/Scala ServiceBus 消费者，重试错误处理

Question

我有简单的服务总线消费者：

val consumeFunc = (context: ServiceBusReceivedMessageContext) => consumeMessageOrder(context, onConsumed)
val queueName = messageType match {
  case MessageBusService.Order => config.ordersQueueName
}

new ServiceBusClientBuilder()
  .connectionString(config.connectionString)
  .processor()
  .queueName(queueName)
  .processMessage { context =>
    consumeFunc(context)
  }
  .processError(context => processErrorOrder(context, countdownLatch))
  .buildProcessorClient()

及错误处理方法：

  def processErrorOrder(context: ServiceBusErrorContext, countdownLatch: CountDownLatch): Unit = {
    import ServiceBusFailureReason._
    context.getException match {
      case e: ServiceBusException
          if List(MESSAGING_ENTITY_DISABLED, MESSAGING_ENTITY_NOT_FOUND, UNAUTHORIZED).contains(
            e.getReason
          ) =>
        log.error(s"An unrecoverable error occurred. Stopping processing with reason ${e.getReason} ${e.getMessage}")
        countdownLatch.countDown()
      case e: ServiceBusException =>
        log.error(s"Error source ${context.getErrorSource}, reason ${e.getReason}, message: ${e}")
    }
  }

它在 scala 中，但代码基于官方教程AzureDocs我找不到方法，在这里创建一些重试策略，如何在这里处理重试以及如果失败 X 重试将失败消息发送到死信队列？

谢谢