测试任一属性是否包含 AssertJ 中的值

Question

具有以下代码：

@Data
@AllArgsConstructor
public class TolkienCharacter{
    String nick;
    String name;
    String surname;
}


@Test
void go(){
    TolkienCharacter frodo = new TolkienCharacter("GoodFrodo", "Frodo", "Baggins");
    TolkienCharacter togo = new TolkienCharacter("Hobbit", "Togo", "Goodbody");
    List<TolkienCharacter> goodCharacters = Arrays.asList(frodo, togo);

我需要编写断言，检查 goodCharacters 列表中的所有元素是否都有昵称或姓氏，其中包含“好”。

最好的方法是什么？

Answer 1

一个解决方案可能是：

assertThat(goodCharacters).extracting(TolkienCharacter::getNick, TolkienCharacter::getSurname)
    .allSatisfy(tuple -> assertThat(tuple.toList()).asInstanceOf(list(String.class))
        .anySatisfy(string -> assertThat(string).containsIgnoringCase("good")));

如果发生故障，错误消息将如下所示：

java.lang.AssertionError: 
Expecting all elements of:
  [("GoodFrodo", "Baggins"), ("Hobbit", "Badbody")]
to satisfy given requirements, but these elements did not:

("Hobbit", "Badbody")
error: 
Expecting any element of:
  ["Hobbit", "Badbody"]
to satisfy the given assertions requirements but none did:

"Hobbit"
error: 
Expecting actual:
  "Hobbit"
to contain:
  "good"
 (ignoring case)

"Badbody"
error: 
Expecting actual:
  "Badbody"
to contain:
  "good"
 (ignoring case)