（已解决-在第 4 个代码中）flask 从 URL 中获取值，并将网站上的所有倍数（例如：4，最多 50）=>（312）相加 [重复]

Question

这个问题已经存在：

python flask 输入多个值，我们如何从 URL 获得的值相乘或进行计算（我该如何更正）[关闭]

7 小时前关闭。

python flask 从 URL 中取值并将所有倍数（例如：4，最多 50）=>（312）在网站上修复。

# import main Flask class and request object
from flask import Flask, request
 
# create the Flask app
app = Flask(__name__)
 
@app.route('/data')
def query_example():

    num = request.args.get('num')

    count = request.args.get('count')


    num_int = int(num)
    count_int = int(count)

    i =1
    sum =0

    while i<=count_int:
       if i % num_int == 0:
          sum+= i
        
          i +=1
    ans = sum

    return ans
         



if __name__ == '__main__':
    # run app in debug mode on port 5000
    app.run(debug=True, port=5000)

代码图片

所需的 URL（图片）例如： http://127.0.0.1:5000/data?num=3&count=50

4到50个简单功能（图片）

我更正的新代码（仍然无法得到“sum2”结果）

 # import main Flask class and request object from re import I from flask import Flask, request # create the Flask app app = Flask(__name__) @app.route('/data') def query_example(): # if key doesn't exist, returns None name = request.args.get('name') # if key doesn't exist, returns a 400, bad request error num1 = request.args['num1'] num2 = request.args['num2'] # take input from string to other variable變數 num1_int = int(num1) num2_int= int(num2) multiply = num1_int*num2_int i=1 sum2=0 for i in range (1, num1_int,1 ): if i % num2_int ==0: sum2+=i i+=1 return ''' <h1>The name is: {}</h1> <h1>The num1 is: {}</h1> <h1>The num2 is: {}</h1> <h1>The multiply is: {}</h1> <h1>The sum2 is: {}</h1> '''.format(name, num1_int,num2_int, multiply,sum2) if __name__ == '__main__': # run app in debug mode on port 5000 app.run(debug=True, port=5000)

我现在确实在外面更改了i +=1 ，但是新代码不起作用。

 # import main Flask class and request object from re import I from flask import Flask, request # create the Flask app app = Flask(__name__) @app.route('/data') def query_example(): # if key doesn't exist, returns None name = request.args.get('name') # if key doesn't exist, returns a 400, bad request error num1 = request.args['num1'] num2 = request.args['num2'] # take input from string to other variable變數 num1_int = int(num1) num2_int= int(num2) multiply = num1_int*num2_int i=1 sum2=0 while i<=num2_int: if i % num1_int ==0: sum+=i i+=1 return ''' <h1>The name is: {}</h1> <h1>The num1 is: {}</h1> <h1>The num2 is: {}</h1> <h1>The multiply is: {}</h1> <h1>The sum2 is: {}</h1> '''.format(name, num1_int,num2_int, multiply,sum2) if __name__ == '__main__': # run app in debug mode on port 5000 app.run(debug=True, port=5000)

第四个密码，被爱的人

 from flask import Flask, request app = Flask(__name__) @app.route('/data') def query_example(): # if key doesn't exist, returns None name = request.args.get('name') num1 = request.args['num1'] num2 = request.args['num2'] num1_float = int(num1) num2_float = int(num2) multiply = num1_float*num2_float i=1 sum2=0 while i< num1_float: if i % num2_float ==0: sum2+=i i+=1 aaa =sum2 return ''' <h1>The name is: {}</h1> <h1>The num1 is: {}</h1> <h1>The num2 is: {}</h1> <h1>The multiply is: {}</h1> <h1>The sum2 is: {}</h1> '''.format(name, num1_float,num2_float, multiply,aaa) if __name__ == '__main__': # run app in debug mode on port 5000 app.run(debug=True, port=5000)

DEMO求解代码图片（将所有2的倍数相加直到20

Answer 1

我复制了第一个代码并尝试修改它。 它就像一个魅力，但不确定它是否是你所期望的。 这是代码：

from flask import Flask, render_template, request

app = Flask(__name__)

@app.route('/data')
def query_example():
    print('Loading data...\n')

    num = request.args.get('num')
    count = request.args.get('count')

    num_int = int(num)
    count_int = int(count)

    print(f'num_int: {num_int}')
    print(f'count_int: {count_int}\n')

    i = 1
    sum = 0

    while i <= count_int:
        if i % num_int == 0:
            sum += i
            
        i += 1

    return render_template('output.html', result=sum)

这是 URL http://localhost:5000/data?num=3&count=50的结果。

[编辑]
您在while中放错了i += 1 。 它应该在if之外，因为第一次迭代从未满足条件。