psycopg 有数据时返回空查询结果

Question

我正在尝试从下面的 postgressql 查询中获取记录。 它确实有数据，但是当我尝试用 psycopg 检索它时，奇怪的是它返回空。 它是否适用于 WITH 查询，或者我们只能使用 SELECT 代替？ 任何输入将不胜感激，谢谢。

query = \
        f""" WITH a AS (
            SELECT "public"."table_a"."code", 
            "public"."table_a"."address", sum("public"."table_a"."amount") AS 
            "sum" FROM "public"."table_a" WHERE "public"."table_a"."address" <> 'KL' GROUP BY 
            "public"."table_a"."code", "public"."table_a"."address"), 
            c as (
                WITH b AS ( 
                SELECT address, code, count(*) as "total" FROM table_b where created_date between 
                ((current_date + TIME '14:00:00.000+08:00') - interval '7 days') and ((
                current_date + TIME '23:59:00.000+08:00') - interval '7 days') group by 
                address, code order by address, code) 
                select b.address, table_c.unit_code, table_c.name, sum(b.total * 
                table_c.amount) as "total" from table_c join b on table_c.code = b.code 
                group by table_c.unit_code, table_c.name, b.address 
                order by table_c.unit_code, b.address
                )
            SELECT a.address, a.code, (a.sum - c.total)::int as output
            FROM a join c on a.code = c.unit_code
            AND a.address = c.address
            ORDER BY a.address, a.code 
"""

conn = psycopg2.connect(**params)
        cur = conn.cursor()
        cur.execute(query)
rows = cur.fetchall()
for row in rows:
            print(row)

Answer 1

我花了一整天的时间才意识到日志中的时间戳与预期的不同。 下面的查询有效（使用 WITH AS 和所有），只需要为我删除时区，因为我不需要它。 学习到教训了。 确保检查服务器时区以及是否需要转换。 希望这对将来的某人有所帮助。

WITH a AS (
            SELECT "public"."table_a"."code", 
            "public"."table_a"."address", sum("public"."table_a"."amount") AS 
            "sum" FROM "public"."table_a" WHERE "public"."table_a"."address" <> 'KL' GROUP BY 
            "public"."table_a"."code", "public"."table_a"."address"), 
            c as (
                WITH b AS ( 
                SELECT address, code, count(*) as "total" FROM table_b where created_date between 
                ((current_date + TIME '14:00:00.000') - interval '7 days') and ((
                current_date + TIME '23:59:00.000') - interval '7 days') group by 
                address, code order by address, code) 
                select b.address, table_c.unit_code, table_c.name, sum(b.total * 
                table_c.amount) as "total" from table_c join b on table_c.code = b.code 
                group by table_c.unit_code, table_c.name, b.address 
                order by table_c.unit_code, b.address
                )
            SELECT a.address, a.code, (a.sum - c.total)::int as output
            FROM a join c on a.code = c.unit_code
            AND a.address = c.address
            ORDER BY a.address, a.code