我有 1 个矩阵，我想将该行中的每个元素相乘。 你能帮帮我吗？

Question

一= [1 2 3
4 2 1
1 3 4]

答案应该是 [6 8 12]

我已经尝试了很多但我无法解决它请帮忙。

Answer 1

import math

a = [[1, 2, 3], [4, 2, 1], [1, 3, 4]]
print([math.prod(r) for r in a])

Answer 2

a= [1, 2, 3, 4, 2, 1, 1, 3, 4]

print([a[idx]*a[idx-1]*a[idx-2] for idx, _ in enumerate(a) if (idx+1)%3==0 ])

Answer 3

您可以使用numpy.prod

import numpy as np

a = [[1, 2, 3], [4, 2, 1],[1, 3, 4]]
print(np.prod(a, 1))

---

[6  8 12]

Answer 4

不使用数学或 numpy：

def product(myList) :
    result = 1
    for i in myList:
        result = result * i
    return result

a = [[1, 2, 3], [4, 2, 1], [1, 3, 4]]
b = [product(l) for l in a]

print(b) # [6, 8, 12]