如何在 C#.Net 中调用 asmx 服务而不添加服务引用

Question

我正在调用 asmx webservice 方法而不添加服务引用，因为 asmx 不提供 wsdl。 我可以从提琴手和 postman 访问 asmx 服务。 它工作正常。 但是，当我尝试从我的 C# 代码中调用它时，它会引发 403 禁止异常。

下面是我的 c# 代码。

internal class Class3
{
    string _soapEnvelope =
    @"<soap:Envelope
        xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance'
        xmlns:xsd='http://www.w3.org/2001/XMLSchema'
        xmlns:soap='http://schemas.xmlsoap.org/soap/envelope/'>
    <soap:Body></soap:Body></soap:Envelope>";

    private string CreateSoapEnvelope()
    {
        Dictionary<string, string> Params = new Dictionary<string, string>();
        Params.Add("aId", "11"); // Add parameterName & Value to dictionary
        Params.Add("cId", "22");
        Params.Add("lId", "20");
        string MethodCall = "<" + "GetSettings" + @" xmlns=""http://tempuri.org/"">";
        string StrParameters = string.Empty;
        foreach (var param in Params)
        {
            StrParameters += string.Format("<{0}>{1}</{0}>", param.Key, param.Value);
        }
        MethodCall = MethodCall + StrParameters + "</" + "GetSettings" + ">";
        StringBuilder sb = new StringBuilder(_soapEnvelope);
        sb.Insert(sb.ToString().IndexOf("</soap:Body>"), MethodCall);
        return sb.ToString();
    }

    private HttpWebRequest CreateWebRequest()
    {
        HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create("sample.asmx");
        webRequest.Headers.Add("SOAPAction", "\"http://tempuri.org/" + "GetSettings" + "\"");
        webRequest.Headers.Add("To", "sample.asmx");
        webRequest.Credentials = CredentialCache.DefaultCredentials;
        webRequest.ContentType = "application/x-www-form-urlencoded";
        webRequest.Accept = "text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,image/apng,*/*;q=0.8,application/signed-exchange;v=b3;q=0.9";
        webRequest.Host = "sample.com";
        webRequest.Headers.Set(HttpRequestHeader.CacheControl, "max-age=0");
        webRequest.Headers.Add("Upgrade-Insecure-Requests: 1");
        webRequest.Headers.Add("Origin", "null");
        webRequest.Headers.Add("Accept-Encoding", "gzip, deflate");
        webRequest.Headers.Add("Accept-Language", "en-US,en;q=0.9,zh-CN;q=0.8,zh-TW;q=0.7,zh;q=0.6");
        webRequest.Method = "POST";
        return webRequest;

    }

    public string InvokeService()
    {
        try
        {
            WebResponse response = null;
            string strResponse = "";
            //Create the request
            HttpWebRequest req = this.CreateWebRequest();
            //write the soap envelope to request stream
            using (Stream stm = req.GetRequestStream())
            {
                using (StreamWriter stmw = new StreamWriter(stm))
                {
                    stmw.Write(this.CreateSoapEnvelope());
                }
            }
            //get the response from the web service
            response = req.GetResponse();
            Stream str = response.GetResponseStream();
            StreamReader sr = new StreamReader(str);
            strResponse = sr.ReadToEnd();
            return HttpUtility.HtmlDecode(strResponse);
        }
        catch (Exception ex)
        {
            return "";
        }
    }

    
}

 internal class Program
{
    static void Main(string[] args)
    {   
        new Class3().InvokeService();
    }
}

也尝试在下面添加标题，但没有任何区别。

 webRequest.ContentLength = 600000;
        webRequest.ProtocolVersion = HttpVersion.Version11;
        webRequest.KeepAlive = false; 
        webRequest.UserAgent = "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/105.0.0.0 Safari/537.36";

我正在使用 VS2022 - 带有.Net Framework 4.6.2 的控制台应用程序

有人可以帮我理解我在这里做错了什么。

Answer 1

经过大量研究，我知道我传递参数的方式是不正确的。 下面是做同样的简单和正确的版本。 它现在工作

            string remoteUrl = "service.asmx";
        string poststring = "aId=11&cId=22&lId=20";

        HttpWebRequest httpRequest = (HttpWebRequest)WebRequest.Create(remoteUrl);
        httpRequest.Host = "host.com";
        httpRequest.Method = "POST";
        httpRequest.ContentType = "application/x-www-form-urlencoded";
        httpRequest.UserAgent = "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/105.0.5195.127 Safari/537.36";

        // Convert the post string to a byte array
        byte[] bytedata = System.Text.Encoding.UTF8.GetBytes(poststring);
        httpRequest.ContentLength = bytedata.Length;

        // Create the stream
        Stream requestStream = httpRequest.GetRequestStream();
        requestStream.Write(bytedata, 0, bytedata.Length);
        requestStream.Close();

        // Get the response from remote server
        HttpWebResponse httpWebResponse = (HttpWebResponse)httpRequest.GetResponse();
        Stream responseStream = httpWebResponse.GetResponseStream();

        System.Text.StringBuilder sb = new System.Text.StringBuilder();
        using (StreamReader reader = new StreamReader(responseStream, System.Text.Encoding.UTF8))
        {
            string line;
            while ((line = reader.ReadLine()) != null)
            {
                sb.Append(line);
            }
        }

        string data = sb.ToString();