删除目录中的 zip 文件

Question

#! /usr/bin/bash

DIRECTORY=/main/dir/sub-dir

if [ -d $DIRECTORY ]; then
      find $DIRECTORY/ '*' -maxdepth 1 -mtime +1 -exec rm -rf {} \;;
#Zip Files generated within the last six hour
      find $DIRECTORY/ '*' -maxdepth 1 -mmin -360 -exec gzip {} \;
   fi

I'm using this command to remove files generated within the last , however the output has the following errors


Error messages :

-bash-4.2$ ./zip_files.sh
find: â*â: No such file or directory
gzip: /main/dir/sub-dir is a directory -- ignored


Files in this directory will be of these sequence, 

-rw------- 1 postgres dba 16777216 Sep 23 23:37 000000010000224300000015
-rw------- 1 postgres dba 16777216 Sep 23 23:37 000000010000224300000016
-rw------- 1 postgres dba 16777216 Sep 23 23:37 000000010000224300000017
-rw------- 1 postgres dba 16777216 Sep 23 23:37 000000010000224300000018
-rw------- 1 postgres dba 16777216 Sep 23 23:37 000000010000224300000019
-rw------- 1 postgres dba 16777216 Sep 23 23:37 00000001000022430000001A

我只想删除已删除和压缩的文件并压缩错误消息

感谢您的回复。

Answer 1

您的脚本可能如下所示。 注意引号，注意不带空格的不带引号的*的用法，注意find arguments，参见man find 。 用 shellcheck 检查你的脚本！

#!/usr/bin/env bash

# prefer upper case variables only for exported variables
directory=/main/dir/sub-dir
if [[ -d "$directory" ]]; then
      find "$directory"/* -maxdepth 1 -type f \
          '(' -mtime +1 -delete ')' -o \
          '(' -mmin -360 -exec gzip {} ';' ')'
fi

使用 bash arrays 您可以在长参数行之间放置注释：

      cmd=(
          find "$directory"/* -maxdepth 1 -type f
          # delete somthing
          '(' -mtime +1 -delete ')' -o
          # gzip them
          '(' -mmin -360 -exec gzip {} ';' ')'
      )
      "${cmd[@]}"