这是 gcc 11.2.1 中与 _GLIBCXX_USE_CXX11_ABI 相关的错误吗？

Question

The following C++ code fails to compile on gcc 11.2.1 on CentOS 7.2.2009 (available through Software Collections only) using the following command:

命令： scl enable devtoolset-11 'g++ -std=c++11 test.cpp -o test'

代码：

#include <iostream>
#include <string>

int main() {

        std::string s="abcdefg";
        s.erase(s.cbegin(), s.cend());
        return 0;
}

错误：

test.cpp: In function 'int main()':
test.cpp:7:16: error: no matching function for call to 'std::basic_string<char>::erase(std::basic_string<char>::const_iterator, std::basic_string<char>::const_iterator)'
    7 |         s.erase(s.cbegin(), s.cend());
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~
In file included from /opt/rh/devtoolset-11/root/usr/include/c++/11/string:55,
                 from /opt/rh/devtoolset-11/root/usr/include/c++/11/bits/locale_classes.h:40,
                 from /opt/rh/devtoolset-11/root/usr/include/c++/11/bits/ios_base.h:41,
                 from /opt/rh/devtoolset-11/root/usr/include/c++/11/ios:42,
                 from /opt/rh/devtoolset-11/root/usr/include/c++/11/ostream:38,
                 from /opt/rh/devtoolset-11/root/usr/include/c++/11/iostream:39,
                 from test.cpp:1:
/opt/rh/devtoolset-11/root/usr/include/c++/11/bits/basic_string.h:4766:7: note: candidate: 'std::basic_string<_CharT, _Traits, _Alloc>& std::basic_string<_CharT, _Traits, _Alloc>::erase(std::basic_string<_CharT, _Traits, _Alloc>::size_type, std::basic_string<_CharT, _Traits, _Alloc>::size_type) [with _CharT = char; _Traits = std::char_traits<char>; _Alloc = std::allocator<char>; std::basic_string<_CharT, _Traits, _Alloc>::size_type = long unsigned int]'
 4766 |       erase(size_type __pos = 0, size_type __n = npos)
      |       ^~~~~
/opt/rh/devtoolset-11/root/usr/include/c++/11/bits/basic_string.h:4766:23: note:   no known conversion for argument 1 from 'std::basic_string<char>::const_iterator' to 'std::basic_string<char>::size_type' {aka 'long unsigned int'}
 4766 |       erase(size_type __pos = 0, size_type __n = npos)
      |             ~~~~~~~~~~^~~~~~~~~
/opt/rh/devtoolset-11/root/usr/include/c++/11/bits/basic_string.h:4783:7: note: candidate: 'std::basic_string<_CharT, _Traits, _Alloc>::iterator std::basic_string<_CharT, _Traits, _Alloc>::erase(std::basic_string<_CharT, _Traits, _Alloc>::iterator) [with _CharT = char; _Traits = std::char_traits<char>; _Alloc = std::allocator<char>; std::basic_string<_CharT, _Traits, _Alloc>::iterator = std::basic_string<char>::iterator]'
 4783 |       erase(iterator __position)
      |       ^~~~~
/opt/rh/devtoolset-11/root/usr/include/c++/11/bits/basic_string.h:4783:7: note:   candidate expects 1 argument, 2 provided
/opt/rh/devtoolset-11/root/usr/include/c++/11/bits/basic_string.h:4803:7: note: candidate: 'std::basic_string<_CharT, _Traits, _Alloc>::iterator std::basic_string<_CharT, _Traits, _Alloc>::erase(std::basic_string<_CharT, _Traits, _Alloc>::iterator, std::basic_string<_CharT, _Traits, _Alloc>::iterator) [with _CharT = char; _Traits = std::char_traits<char>; _Alloc = std::allocator<char>; std::basic_string<_CharT, _Traits, _Alloc>::iterator = std::basic_string<char>::iterator]'
 4803 |       erase(iterator __first, iterator __last);
      |       ^~~~~
/opt/rh/devtoolset-11/root/usr/include/c++/11/bits/basic_string.h:4803:22: note:   no known conversion for argument 1 from '__normal_iterator<const char*,[...]>' to '__normal_iterator<char*,[...]>'
 4803 |       erase(iterator __first, iterator __last);
      |             ~~~~~~~~~^~~~~~~

该错误意味着编译器无法找到方法std::string::erase(const_iterator, const_iterator) ，该方法应该在 C++11 中可用（根据此参考）。

相同的代码在使用相同版本的 gcc 的其他操作系统上编译良好（例如这里）

我能够找到导致 CentOS 与其他发行版中编译器宏_GLIBCXX_USE_CXX11_ABI定义的行为差异的原因。 大多数发行版启用_GLIBCXX_USE_CXX11_ABI而 CentOS 强制禁用它，如此处所述。 在此处查看有关宏的更多信息。

我目前对宏_GLIBCXX_USE_CXX11_ABI的理解是这样的：

• 从 gcc 5 开始，由于 C++11 中不允许写入时复制，引入了std::basic_string的 ABI 发生了变化。
• 但是，这不应更改承诺与 C++11 一起提供的 API。
• 因此，无论我选择哪种 ABI， std::basic_string::erase(const_iterator, const_iterator)都应该可用。

但是，我观察到的是方法std::basic_string::erase(const_iterator, const_iterator)在较旧的 ABI 中根本不可用（即当_GLIBCXX_USE_CXX11_ABI=0时。

这是 gcc 中的错误，还是我对宏_GLIBCXX_USE_CXX11_ABI的理解有问题？