PyQt5 getOpenFileName 在脚本中崩溃，但在 Python 解释器中正常运行

Question

对于以下名为temp.py的测试脚本：

from PyQt5 import Qt
Qt.QApplication([])
print(1)
a = Qt.QFileDialog.getOpenFileName(None,"aaa",r"C:")
print(2)

当我使用python temp.py运行它时，程序崩溃而没有回溯：

C:\Anaconda3\python.exe E:/xxxxxx/xxxxxx/xxxxxx/temp.py 
1

Process finished with exit code -1073741819 (0xC0000005)

但是，当我将命令复制到 python 解释器中时，它运行正常：

PS E:\My_Program> python
Python 3.9.7 (default, Sep 16 2021, 16:59:28) [MSC v.1916 64 bit (AMD64)] :: Anaconda, Inc. on win32

Warning:
This Python interpreter is in a conda environment, but the environment has
not been activated.  Libraries may fail to load.  To activate this environment
please see https://conda.io/activation

Type "help", "copyright", "credits" or "license" for more information.
>>> from PyQt5 import Qt
>>> Qt.QApplication([])
<PyQt5.QtWidgets.QApplication object at 0x0000027579767DC0>
>>> print(1)
1
>>> a = Qt.QFileDialog.getOpenFileName(None,"aaa",r"C:")  # here, the getOpenFileName window popup and I selected C:/Anaconda3/vcomp140.dll
>>> print(2)
2
>>>
>>> print(a)
('C:/Anaconda3/vcomp140.dll', 'All Files (*)')
>>>
>>> import sys
>>> print(sys.executable) # to confirm that it's the same executable
C:\Anaconda3\python.exe

此外，其他 PyQt5 功能似乎工作正常。 例如，我可以启动 QtDesigner 设计的简单小部件，它显示正确的 window。

我该如何解决这个问题？