我如何使用错误的公式？ （使用嵌套平方根计算 PI）

Question

我想用 Viete 的 2 嵌套平方根公式计算 pi 的近似值

#include <iostream>
#include <iomanip>
#include <cmath>

using namespace std;
int main()
{
    int k; //variable for user input
    int n = 1; //built integer that causes the program to loop
    double result;
    //greeting message, start of program
    cout << "Welcome to the Approx PI program.\n";
    cout << "Please enter in a value for k...\n";
    cin >> k;
    //if user inputs a number outside the interval
    while (k < 1 || k > 30)
    {
        cout << "Invalid ---k must be >=1 and <=30\n";
        cout << "Please enter in a value for k...\n";
        cin >> k;
    }
    //calculating PI with the nested square root formula
    while (n <= k - 1)
    {
        result = sqrt(2 + result);
        n++;
    }
    result = pow(2, k) * sqrt(2 - result);
    //outputs the result, end of program
    cout << "Approx PI =         " <<setprecision(20)<<fixed<<result<<endl;
    return 0;
}

但是当我输入 28 时，它给了我 4：

Welcome to the Approx PI program.
Please enter in a value for k...
28
Approx PI =         4

Process finished with exit code 0

当我输入 29 或 30 时，结果为 0：

Welcome to the Approx PI program.
Please enter in a value for k...
30
Approx PI =         0

Process finished with exit code 0

我认为 k=30 应该给我：

Approx PI = 3.14245127249413367895

我究竟做错了什么？

Answer 1

当您声明result时，您应该为其分配一些值。 否则，您会导致未定义的行为，因为在第 25 行您使用未初始化的 memory result 。