mysql：获取达到目标的最短日期

Question

我希望这个描述是清楚的：

我有一个包含以下字段的表：

用户身份	order_id	创建日期	分数	姓名
u.id_1	o.id_1	日期_1	0.0024	一些名字
u.id_2	o.id_2	日期_2	0.0053	一些名字

我想要另一个字段，它告诉我每个 user_id 是它获得至少 0.05 个分数的最小日期。

我有这个查询

SELECT r.user_id as user_id,
       r.id as order_id,
       r.created_at as creation_date,
       r.fraction as fractions,
       r.mining_name as name,
       SUM(r.fraction) OVER (PARTITION BY r.user_id ORDER BY r.created_at) as growing_sum,
       CASE WHEN SUM(r.fraction) OVER (PARTITION BY r.user_id ORDER BY r.created_at) >=0.05 THEN TRUE ELSE FALSE END AS isInClub500
FROM yield_mining_rent r
ORDER BY user_id, creation_date

它告诉我是否告诉我一个累积总和，以及我是否超过 0.5 个分数，但我也想要一个字段。

我知道如果我像这样使用 CTE，我可以做到这一点：

WITH CTE AS (SELECT r.user_id                                                           as user_id,
                    r.id                                                                as order_id,
                    r.created_at                                                        as creation_date,
                    r.fraction                                                          as fractions,
                    r.mining_name                                                       as name,
                    SUM(r.fraction) OVER (PARTITION BY r.user_id ORDER BY r.created_at) as growing_sum,
                    CASE
                        WHEN SUM(r.fraction) OVER (PARTITION BY r.user_id ORDER BY r.created_at) >= 0.05 THEN TRUE
                        ELSE FALSE END                                                  AS isInClub500
             FROM yield_mining_rent r
             ORDER BY user_id, creation_date
)
SELECT user_id,
       min(creation_date)
FROM CTE
WHERE isInClub500 = true
GROUP BY user_id

但我的问题是：有没有办法在没有 CTE 的情况下得到这个？ 太感谢了