创建新的 object 数组并将对象合并到具有相同键值的数组 object 中

Question

这可能看起来有点奇怪，但我需要将现有数据集中的对象合并到按特定键值分组的新数据集中。 这是数据集：

const object = [
  {
    id: 1,
    scheduledAt: '2022-09-20',
    organization: {
      name: 'Organization 1'
    }
  },
  {
    id: 2,
    scheduledAt: '2022-09-10',
    organization: {
      name: 'Organization 2'
    } 
  },
  {
    id: 3,
    scheduledAt: '2022-09-20',
    organization: {
      name: 'Organization 3'
    }
  }
]

这是我作为返回数据集所追求的：

const objectMerged = {
  '2022-09-20': [
    {
      id: 1,
      scheduledAt: '2022-09-20',
      organization: {
        name: 'Organization 1'
      }
    },
    {
      id: 3,
      scheduledAt: '2022-09-20',
      organization: {
        name: 'Organization 3'
      }
    }
  ],
  '2022-09-10': [
    {
      id: 2,
      scheduledAt: '2022-09-10',
      organization: {
        name: 'Organization 2'
      } 
    }
  ]
}

我尝试了许多不同的方法，但似乎没有任何工作正常。 这是最新的代码，它不起作用：

const merged = []

object.forEach((item) => {
  if (!merged.length) {
    // if the return dataset is empty, add this item immediately
    merged.push({ [item.scheduledAt]: [item] }
  } else {
    // check if item already exists with the same scheduledAt as current object and if so, push it into that array as object
    // if does not exist, create new array entry with the new scheduledAt name

    const find = Object.keys(merged).map((k) => {
      console.log(`key ${k}`)
      console.log(merged[k])
    
      return Object.keys(merged[k]).map((key) => {
        console.log(`key2: ${key}`)
    
        return key === item.scheduledAt
      })
    })

    console.log(find)
  }
})

console.log(merged)

任何帮助是极大的赞赏。 谢谢！

Answer 1

通过使用 reduce，您可以生成所需的内容。 请看一看：

 const object = [ { id: 1, scheduledAt: '2022-09-20', organization: { name: 'Organization 1' } }, { id: 2, scheduledAt: '2022-09-10', organization: { name: 'Organization 2' } }, { id: 3, scheduledAt: '2022-09-20', organization: { name: 'Organization 3' } }, ]; const objectMerged = object.sort((objectA, objectB) => objectA.scheduledAt.localeCompare(objectB.scheduledAt) ).reduce((acc, cur) => ({...acc, [cur.scheduledAt]: [...(acc[cur.scheduledAt] || []), cur, ], }), {}); console.log(objectMerged);