python - 我们 ResourceWarning 没有错误

Question

如果我采用这样一个简单的测试脚本，它会导致 ResourceWarning：

import asyncio
import aiohttp

async def main():
    client = aiohttp.ClientSession()
    await client.get("https://google.com")

asyncio.run(main())

使用python -bb -We -X dev test.py运行它。

我期望ResourceWarning出错并导致非 0 退出代码。

实际结果：

Exception ignored in: <function ClientSession.__del__ at 0x7f397e04beb0>
Traceback (most recent call last):
  File "/home/s/.local/lib/python3.8/site-packages/aiohttp/client.py", line 342, in __del__
    _warnings.warn(
ResourceWarning: Unclosed client session <aiohttp.client.ClientSession object at 0x7f397dfce4b0>
Exception ignored in: <function BaseConnector.__del__ at 0x7f397e0b6eb0>
Traceback (most recent call last):
  File "/home/s/.local/lib/python3.8/site-packages/aiohttp/connector.py", line 281, in __del__
    _warnings.warn(f"Unclosed connector {self!r}", ResourceWarning, **kwargs)
ResourceWarning: Unclosed connector <aiohttp.connector.TCPConnector object at 0x7f397dfce690>
Exception ignored in: <socket.socket fd=7, family=AddressFamily.AF_INET, type=SocketKind.SOCK_STREAM, proto=6, laddr=('192.168.1.18', 45750), raddr=('172.217.169.4', 443)>
ResourceWarning: unclosed <socket.socket fd=7, family=AddressFamily.AF_INET, type=SocketKind.SOCK_STREAM, proto=6, laddr=('192.168.1.18', 45750), raddr=('172.217.169.4', 443)>
Exception ignored in: <function _SelectorTransport.__del__ at 0x7f397e8264b0>
Traceback (most recent call last):
  File "/usr/lib/python3.8/asyncio/selector_events.py", line 696, in __del__
    _warn(f"unclosed transport {self!r}", ResourceWarning, source=self)
ResourceWarning: unclosed transport <_SelectorSocketTransport fd=7>
Exception ignored in: <function _SelectorTransport.__del__ at 0x7f397e8264b0>
Traceback (most recent call last):
  File "/usr/lib/python3.8/asyncio/selector_events.py", line 696, in __del__
    _warn(f"unclosed transport {self!r}", ResourceWarning, source=self)
ResourceWarning: unclosed transport <_SelectorSocketTransport fd=6>
Exception ignored in: <socket.socket fd=6, family=AddressFamily.AF_INET, type=SocketKind.SOCK_STREAM, proto=6, laddr=('192.168.1.18', 42986), raddr=('142.250.187.206', 443)>
ResourceWarning: unclosed <socket.socket fd=6, family=AddressFamily.AF_INET, type=SocketKind.SOCK_STREAM, proto=6, laddr=('192.168.1.18', 42986), raddr=('142.250.187.206', 443)>

0 退出代码表示成功。

我如何确保程序在警告时实际失败？

Answer 1

-We让解释器引发异常而不是警告。 但是，在__del__ function 内不会引发异常。 相反，此类异常会打印到 stderr 并继续执行。 可以通过sys.unraisablehook覆盖此行为。

这是将返回非零退出代码的代码的修改版本：

import aiohttp
import asyncio
import os
import sys


def custom_hook(args):
    os._exit(7)


async def main():
    client = aiohttp.ClientSession()
    await client.get("https://google.com")


sys.unraisablehook = custom_hook
asyncio.run(main())

请注意，我使用os._exit() sys.exit() 那是因为sys.exit()引发了 SystemExit 异常，这在我们的例子中是个坏主意。