“架构 x86_64 的未定义符号”使用 g++

Question

我正在编译一个简单的“Hello world”程序 hw.cpp。 看起来像这样

#include <iostream>
#include <string>
using namespace std;
int main() {
  cout << "Hello world!" << endl;
  return 0;
}

我在 OS X 上运行。我使用以下命令编译： g++ hw.cp但是收到一条错误消息：

ld: warning: ignoring file /usr/local/lib/libc++.so, building for macOS-x86_64 but attempting to link with file built for unknown-unsupported file format ( 0x49 0x4E 0x50 0x55 0x54 0x28 0x6C 0x69 0x62 0x63 0x2B 0x2B 0x2E 0x73 0x6F 0x2E )
Undefined symbols for architecture x86_64:
  "std::__1::locale::use_facet(std::__1::locale::id&) const", referenced from:
      std::__1::ctype<char> const& std::__1::use_facet<std::__1::ctype<char> >(std::__1::locale const&) in hw-a865c1.o
  "std::__1::ios_base::getloc() const", referenced from:
      std::__1::basic_ios<char, std::__1::char_traits<char> >::widen(char) const in hw-a865c1.o
  "std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >::__init(unsigned long, char)", referenced from:
      std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >::basic_string(unsigned long, char) in hw-a865c1.o
  "std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >::~basic_string()", referenced from:
      std::__1::ostreambuf_iterator<char, std::__1::char_traits<char> > std::__1::__pad_and_output<char, std::__1::char_traits<char> >(std::__1::ostreambuf_iterator<char, std::__1::char_tr

就这样一直持续到最后两行：

ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)

什么可能导致此错误？ 我最感兴趣的是了解为什么会这样。

Answer 1

这是有效的

brew reinstall gcc
/usr/local/bin/g++-12 hw.cpp

我需要专门引用 GNU 编译器，而且我还必须事先重新安装它。