如何扫描新的aadhaar卡二维码并将其转换为xml或object？

Question

我正在尝试将 base10 编码数据转换为 base64 或 xml 或任何可读格式，但没有成功。

扫描二维码后的数据是这样的：

我已经尝试使用旧的 adhar 二维码扫描，它给出了 xml 格式，我正在解析和获取数据但是如果扫描新的 adhar 二维码以上述格式获取，我也不知道它是哪种格式。 我需要解码这些数据并获得正确的格式，如 xml 或 object 格式。

这是我的代码：

    if (view == qr_check_box) {
        Intent intent = new Intent(AbhaCard.this, ScanActivty.class);
        startActivityForResult(intent, abhaQr);
    }

    protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == abhaQr && resultCode == RESULT_OK) {
        if (data != null) {
            Barcode barcode = data.getParcelableExtra("barcode");
            if (barcode != null && barcode.displayValue != null) {
                try {
                    // Serializer(Simple library) is used for parsing xml data to object
                    Serializer serializer = new Persister();
                    String barcode_sting = barcode.displayValue; 
                    scanResult.setText(barcode_sting);
                    Log.e("QR_code", barcode_sting);
                     try (InputStream stream = new ByteArrayInputStream(barcode_sting.getBytes())) {
                   // this serializer is user for converting xml to object(PrintLetterBarcodeData) in          case of old  adhar card scanning , so i want for new adhar cared qr code , how to convert.
                        barcodeData = serializer.read(PrintLetterBarcodeData.class, stream);
                    } catch (IOException e) {
                        e.printStackTrace();
                    }}**

// 这是我的 PrintLetterBarcodeData class 用于将 xml 解析为 object

     @Root(name = "PrintLetterBarcodeData")
     public class PrintLetterBarcodeData {
     @Attribute(name = "uid")
     private String uid;
     @Attribute(name = "name")
     private String name;
     @Attribute(name = "gender")
     private String gender;
     @Attribute(name = "yob")
     private String yob;
     @Attribute(name = "co")
     private String co;
     @Attribute(name = "house")
     private String house;
     @Attribute(name = "street")
     private String street;
     @Attribute(name = "vtc")
     private String vtc;
     @Attribute(name = "po")
     private String po;
     @Attribute(name = "dist")
     private String dist;
     @Attribute(name = "subdist")
     private String subdist;
     @Attribute(name = "state")
     private String state;
     @Attribute(name = "pc")
     private String pc;
     @Attribute(name = "dob")
     private String dob;}

Answer 1

这是 python 的解决方案，如果有人知道 python 请转换成 java 将代码发送到这里。

      import zlib
      details = ["version","email_mobile_status","referenceid", "name", "dob", 
      "gender", 
       "careof", "district", "landmark",                         "house", 
       "location", 
       "pincode", "postoffice", "state", "street", "subdistrict", "vtc"]
       delimeter = [-1]
       data = {}
       def initializeData(base10encodedData):
        bytes_array = base10encodedData.to_bytes(5000, 'big').lstrip(b'\x00')
         decompressed_array = zlib.decompress(bytes_array, 16 + zlib.MAX_WBITS)
        if not decompressed_array[0:2].decode("ISO-8859-1") == 'V2':
         details.pop(0)
         for i in range(len(decompressed_array)):
         if decompressed_array[i] == 255:
         delimeter.append(i)

         for i in range(len(details)):
         data[details[i]] = decompressed_array[delimeter[i] + 1:delimeter[i + 
         1]].decode("ISO-8859-1")
          data['adhaar_last_4_digit'] = data['referenceid'][0:4]
          data['adhaar_last_digit'] = data['referenceid'][3]
          data['mobile'] = False
          if int(data['email_mobile_status']) == 3 or 
          int(data['email_mobile_status']) == 2:
          data['mobile'] = True