在本地存储来自 Google Colab 的字典变量

Question

在 Google Colab 中，我创建了一个dict文件名list_dict 。 如何将其腌制并存储在本地？

PATH = <LOCAL_PATH>
pickle_out = open(PATH +'<FILE_NAME>.pickle', 'wb')
pickle.dump(list_dict, pickle_out)
pickle_out.close()

但是，这返回：

---------------------------------------------------------------------------
FileNotFoundError                         Traceback (most recent call last)
<ipython-input-64-439362c7678e> in <module>
----> 1 pickle_out = open(PATH , 'wb')
      2 pickle.dump(list_dict, pickle_out)
      3 pickle_out.close()

FileNotFoundError: [Errno 2] No such file or directory:

如何在本地存储此变量？

Answer 1

以下方法有效：

from google.colab import auth
from googleapiclient.discovery import build
from googleapiclient.errors import HttpError
from googleapiclient.http import MediaFileUpload
import pickle

with open('data.pickle', 'wb') as handle:
    pickle.dump(list_dict, handle, protocol=pickle.HIGHEST_PROTOCOL)

#Authenticate and construct the Drive API client
auth.authenticate_user()
drive_service = build('drive', 'v3')

file_metadata = {'name': 'data.pickle'}
media = MediaFileUpload('data.pickle', mimetype='application/octet-stream')
file = drive_service.files().create(body=file_metadata, media_body=media,
                                    fields='id').execute()
print(F'File ID: {file.get("id")}')

然后，文件data.pickle存储在 Google Drive 的根目录中，可以从那里下载。

Answer 2

尝试使用：

PATH = <LOCAL_PATH>
pickle_out = open(PATH +'<FILE_NAME>.pickle', 'wt')
pickle.dump(list_dict, pickle_out)
pickle_out.close()

或者

PATH = <LOCAL_PATH>
pickle_out = oprn(PATH +'<FILE_NAME>.pickle', 'w')
pickle.dump(list_dict, pickle_out)
pickle_out.close()