按列值对数据行进行分组，然后存储嵌套数据、第一次和最后一次出现以及每组内的计数

Question

我正在尝试拆分以空格分隔的字符串数组，按特定列分组，然后将数据存储在每个组中更方便的结构中。

样本数据：

$dataArray = [
    0 => "AAAAA 2023 01 25 01:04:00 ID:20fjrjeZZ",
    1 => "AAAAA 2023 01 25 01:18:08 ID:13454B43A",
    2 => "AAAAA 2023 01 25 02:00:02 ID:18f5hjeWe",
    3 => "AAAAA 2023 01 25 04:10:13 ID:13454B43A",
    4 => "BBBBB 2023 01 25 01:44:10 ID:Xj74320fj",
    5 => "BBBBB 2023 01 25 07:08:58 ID:13454B43A",
    6 => "BBBBB 2023 01 25 08:40:52 ID:Ftzkk800Y",
    7 => "BBBBB 2023 01 25 14:10:13 ID:18f5hjeWe"
];

我将空间上的行拆分为：

$lines = explode(' ', $dataArray);

然后我想将各个部分（AAAA、2023、01、...）推入一个数组。

foreach($dataArray as $parts){
    $spotArray[] = $parts[$parts][0];
    $yearArray[] = $parts[$parts][1];
    // ...
}

然后用新的数组部分构建一个新结构：

foreach($dataArray as $key => $value){
    $desiredArray[] = $spotArray[["user"[$yearArray[$hourArray]]], "first"[/** ... */]];
    //...
}

预期结果：

$desiredArray = [
    "AAAAA" => [
        "user" => [
            "ID:20fjrjeZZ" => ["01:04:00"],
            "ID:13454B43A" => ["01:18:08", "04:10:12"],
            "ID:18f5hjeWe" => ["02:00:02"]
        ],
        "first" => "01:04:00",
        "last" => "04:10:12",
        "totaUser" => 3,
        "totalAccess" => 4
    ],
    "BBBBB" => [
        "user" => [
            "ID:Xj74320fj" => ["01:44:10"],
            "ID:13454B43A" => ["07:08:58"],
            "ID:Ftzkk800Y" => ["08:40:52"],
            "ID:18f5hjeWe" => ["14:10:13"]
        ],
        "first" => "01:44:10",
        "last" => "14:10:13",
        "totaUser" => 4,
        "totalAccess" => 4
    ]
];

Answer 1

您可以在这里找到问题的答案

<?php

$dataArray = [
        0 => "AAAAA 2023 01 25 01:04:00 ID:20fjrjeZZ",
        1 => "AAAAA 2023 01 25 01:18:08 ID:13454B43A",
        2 => "AAAAA 2023 01 25 02:00:02 ID:18f5hjeWe",
        3 => "AAAAA 2023 01 25 04:10:13 ID:13454B43A",
        4 => "BBBBB 2023 01 25 01:44:10 ID:Xj74320fj",
        5 => "BBBBB 2023 01 25 07:08:58 ID:13454B43A",
        6 => "BBBBB 2023 01 25 08:40:52 ID:Ftzkk800Y",
        7 => "BBBBB 2023 01 25 14:10:13 ID:18f5hjeWe"
    ];
    
$finalArr = array();
$count_arr = array();
$count_arr1 = array();
foreach($dataArray as $parts){    
    $lines = explode(' ', $parts);
    $finalArr[$lines[0]]['user'][$lines[5]][] = $lines[4];
    $count_arr1[$lines[0]]['user'][$lines[5]] = $lines[4];
    $count_arr[$lines[0]][] = 1;

}
foreach($finalArr as $key => $parts){   
    $finalArr[$key]['first'] = reset($count_arr1[$key]['user']);
    $finalArr[$key]['last'] = end($count_arr1[$key]['user']);
    $finalArr[$key]['totaUser'] = count($finalArr[$key]['user']);
    $finalArr[$key]['totalAccess'] = count($count_arr[$key]);
}
print_r($finalArr);

Answer 2

根本不需要运行两个循环。

解析数组中以空格分隔的字符串，并在迭代时构建/覆盖/求和。

代码：（演示）

foreach ($dataArray as $row) {
    [$group, $y, $m, $d, $t, $id] = explode(' ', $row);
    $result[$group]['user'][$id][] = $t;  // accumulate nested elements
    $result[$group]['first'] ??= $t; // only store the first occurrence
    $result[$group]['last'] = $t; // keep overwriting each time
    $result[$group]['totaluser'] = count($result[$group]['user']); // count what is accumulated
    $result[$group]['totalAccess'] = ($result[$group]['totalAccess'] ?? 0) + 1; // increment
}
var_export($result);

---

如果愿意，您甚至可以安全地删除未使用的$y 、 $m和$d声明。 （演示）