填充或减少 python 中的列表中间值

Question

我有很多带有序列坐标但长度不同的列表。 我需要创建 function 来预处理这个列表并返回一个长度为 30 的列表，其中填充了中间值或减少（并重新计算）。

例如，对于 10 长度输出（填充）：

input = [1, 3, 5, 7, 9, 8, 5, 4] # length = 8
output = [1, 2.3, 3, 5, 7, 9, 8, 6.3, 5, 4] # length = 10 

对于 10 长度输出（减少）：

input = [1, 3, 4, 5, 6, 7, 8, 9, 8, 6, 5, 4] # length = 12
output = [1, 2.5, 3.9, 5, 6.5, 7.9, 8.8, 6.5, 5, 4] # length = 10

Answer 1

我想做这样的事情，抱歉解释不当

def normalize_length_of_sequence(sequence, sequence_length=30):
    if len(sequence) < sequence_length:
        while len(sequence) != sequence_length:
            diff_in_seq_ind = np.diff(sequence).argmax()
            new_mean_walue = (sequence[diff_in_seq_ind] + sequence[diff_in_seq_ind+1]) / 2
            sequence.insert(diff_in_seq_ind + 1, new_mean_walue)
    elif len(sequence) > sequence_length:
            while len(sequence) != sequence_length:
                diff_in_seq_ind = np.abs(np.diff(sequence)).argmin()
                sequence.pop(diff_in_seq_ind)
    return sequence