如何使用 powershell 脚本添加新的 3 行以响应 nginx.conf 文件中的特定 3 行

Question

例如nginx.conf文件中，删除下面3行，添加$replace中的值

log_format  main  '$remote_addr - $remote_user [$time_local] "$request" '
                   '$status $body_bytes_sent "$http_referer" '
                   '"$http_user_agent" "$http_x_forwarded_for"';

$替换=

 log_format  main  '$remote_addr - $remote_user $time_iso8601 [$request_time] "$request" '
                     '$status $body_bytes_sent "$http_referer" '
                     '"$http_user_agent" "$http_x_forwarded_for"';

这是我的剧本

$Nginx_home = "I:\nginx\nginx-1.22.1"
$filePath = "$Nginx_home\conf\nginx.conf"

$now = (Get-Date).tostring("MM-dd-yyyy_HH_mm_ss")

Copy-Item -Path "$filePath" -Destination "$Nginx_home\conf\nginx_$now.conf" -PassThru



$Find = {
    log_format  main  '$remote_addr - $remote_user [$time_local] "$request" '
                    '$status $body_bytes_sent "$http_referer" '
                    '"$http_user_agent" "$http_x_forwarded_for"';
}


$Replace = {
    log_format  main  '$remote_addr - $remote_user $time_iso8601 [$request_time] "$request" '
                        '$status $body_bytes_sent "$http_referer" '
                        '"$http_user_agent" "$http_x_forwarded_for"';
}


(Get-Content $Nginx_home\conf\nginx.conf -raw) -replace ([regex]::escape($Find)), $Replace | Set-Content $Nginx_home\conf\nginx1.conf

Answer 1

您可以使用 RegEx 来替换它，您只需要使用-raw读取文件以将其作为多行字符串获取，这样您就可以一次全部替换它。

$Find = @'
log_format  main  '$remote_addr - $remote_user [$time_local] "$request" '
                   '$status $body_bytes_sent "$http_referer" '
                   '"$http_user_agent" "$http_x_forwarded_for"';
'@

$Replace = @'
 log_format  main  '$remote_addr - $remote_user $time_iso8601 [$request_time] "$request" '
                     '$status $body_bytes_sent "$http_referer" '
                     '"$http_user_agent" "$http_x_forwarded_for"';
'@
(Get-Content nginx.conf -raw) -replace ([regex]::escape($Find)), $Replace | Set-Content nginx.updated.conf