
[英]When I try to do routing I get a parse error in ASP.NET Web Forms
[英]when try to add check box to grid view on asp.net forms i get error?
我在 asp.net web forms 和 c# 上工作 我需要添加复选框列作为 gridview 的最后一列
但我不知道如何添加
static string con =
"Data Source=DESKTOP-L558MLK\\AHMEDSALAHSQL;" +
"Initial Catalog=UnionCoop;" +
"User id=sa;" +
"Password=321;";
SqlConnection conn = new SqlConnection(con);
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack)
{
GridViewSearch.DataSource = GetDataForSearch();
GridViewSearch.DataBind();
}
}
public DataTable GetDataForSearch()
{
string response = string.Empty;
SqlCommand cmd = new SqlCommand();
DataTable dt = new DataTable();
try
{
conn.Open();
cmd.Connection = conn;
cmd.CommandText = "select top 10 datelogged AS EntredDatetime, Doc_type AS OrderType, Printer_name, BranchID AS BranchCode, id from Print_Report";
cmd.CommandType = CommandType.Text;
cmd.CommandTimeout = 50000;
SqlDataAdapter sda = new SqlDataAdapter(cmd);
sda.Fill(dt);
}
catch (Exception ex)
{
response = ex.Message;
}
finally
{
cmd.Dispose();
conn.Close();
}
return dt;
}
on aspx page
<asp:GridView ID="GridViewSearch" runat="server">
</asp:GridView>
GridViewSearch.DataSource = GetDataForSearch();
DataGridViewCheckBoxColumn checkColumn = new DataGridViewCheckBoxColumn();
checkColumn.Name = "X";
checkColumn.HeaderText = "X";
checkColumn.Width = 50;
checkColumn.ReadOnly = false;
checkColumn.FillWeight = 10; //if the datagridview is resized (on form resize) the checkbox won't take up too much; value is relative to the other columns' fill values
GridViewSearch.Columns.Add(checkColumn);
GridViewSearch.DataBind();
我在下面的行中收到错误
GridViewSearch.Columns.Add(checkColumn);
参数 1 无法从 system.windows.forms.datagridviewcheckbox 转换为 system.web.ui.webcontrol.databoundfield
那么如何解决这个问题呢?
在我看来,如果您想说一个按钮、复选框或下拉菜单?
为什么不将其添加到标记中。
所以,像这样说:
<div id="MyGridPick" runat="server" style="display:normal;width:40%">
<asp:Label ID="lblSel" runat="server" Text="" Font-Size="X-Large"></asp:Label>
<br />
<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False"
DataKeyNames="ID" cssclass="table table-hover" OnRowDataBound="GridView1_RowDataBound" >
<Columns>
<asp:BoundField DataField="FirstName" HeaderText="FirstName" />
<asp:BoundField DataField="LastName" HeaderText="LastName" />
<asp:BoundField DataField="City" HeaderText="City" />
<asp:BoundField DataField="HotelName" HeaderText="HotelName" ItemStyle-Width="120px" />
<asp:BoundField DataField="Description" HeaderText="Description" />
<asp:TemplateField HeaderText="Select" ItemStyle-HorizontalAlign="Center">
<ItemTemplate>
<asp:CheckBox ID="chkSel" runat="server" />
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
</div>
然后我要加载的代码是这样的:
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack)
LoadGrid();
}
void LoadGrid()
{
SqlCommand cmdSQL =
new SqlCommand("SELECT * FROM tblHotelsA ORDER BY HotelName");
GridView1.DataSource = MyRstP(cmdSQL);
GridView1.DataBind();
}
现在,我当然厌倦了一遍又一遍地输入连接字符串。 所以,我有一个像这样的“通用”例程:
public DataTable MyRstP(SqlCommand cmdSQL)
{
DataTable rstData = new DataTable();
using (SqlConnection conn = new SqlConnection(Properties.Settings.Default.TEST4))
{
cmdSQL.Connection = conn;
using (cmdSQL)
{
conn.Open();
rstData.Load(cmdSQL.ExecuteReader());
}
}
return rstData;
}
以及上面运行的结果:
因此,当您只需将一个复选框放入 gridview 时,很难“添加”一个复选框控件。
按钮也是如此,也许我们想要一个按钮来“查看”或编辑上面的行,或类似的东西。
所以,再一次,只需放入一个简单的简按钮,这样说:
<asp:TemplateField HeaderText="View" ItemStyle-HorizontalAlign="Center" >
<ItemTemplate>
<asp:Button ID="bView" runat="server" Text="View" CssClass="btn"
OnClick="bView_Click" />
</ItemTemplate>
</asp:TemplateField>
现在我们有了这个:
甚至更好?
那么,既然那个按钮(或复选框)是一个普通的简标准控件?
然后你可以添加标准事件,比如点击事件,或者你想要的任何东西。
为按钮单击说出此代码(显示如何获取当前行)。
protected void bView_Click(object sender, EventArgs e)
{
Button btn = sender as Button;
GridViewRow gRow = btn.NamingContainer as GridViewRow;
int PKID = (int)GridView1.DataKeys[gRow.RowIndex]["ID"];
SqlCommand cmdSQL =
new SqlCommand("SELECT * FROM tblHotelsA WHERE ID = @ID");
cmdSQL.Parameters.Add("@ID", SqlDbType.Int).Value = PKID;
DataTable dtHotel = MyRstP(cmdSQL);
General.FLoader(MyEditArea, dtHotel.Rows[0]);
MyGridPick.Style.Add("display", "none"); // hide grid
MyEditArea.Style.Add("display", "normal"); // show edit div area
}
我们现在得到/看到这个:
这:
protected void cmdSelProcess_Click(object sender, EventArgs e)
{
// process all rows in GV with check box
String sPK = "";
List<int> MySelected = new List<int>();
foreach (GridViewRow gRow in GridView1.Rows)
{
CheckBox chkSel = (CheckBox)gRow.FindControl("chkSel");
if (chkSel.Checked)
{
int PK = (int)GridView1.DataKeys[gRow.RowIndex]["ID"];
// add pk value of row to our list
MySelected.Add(PK);
// Or we could process data based on current gRow
if (sPK != "")
sPK += ",";
sPK += PK.ToString();
Debug.Print(PK.ToString());
}
}
// at this point, we have a nice list of selected in MySelected
// or, maybe process as a data table
SqlCommand cmdSQL =
new SqlCommand($"SELECT * FROM tblHotelsA where ID IN({sPK})");
DataTable rstSelected = MyRstP(cmdSQL);
//
foreach (DataRow dr in rstSelected.Rows)
{
// do whatever
}
}
Datagridviewcheckboxcolumn 是一个 Windows formx object。你在 web forms 工作。有关webforms 复选框字段的信息,请参阅下面的链接
CheckBoxField checkColumn = new CheckBoxField();
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