将 object 转换为带对象的数组

Question

我需要帮助解决这个问题，我尝试了 object.keys 和 map，但不能走得太远，所以，我有这个 object，每个键都有一个数组：

const first = {
    "apples": [
        "5.78",
        "3.96",
        "3.71"
    ],
    "oranges": [
        "54.25",
        "41.29",
        "33.44"
    ],
    "cucumbers": [
        "97.28",
        "97.13",
        "95.95"
    ],
    "carrots": [
        "6.48",
        "5.1",
        "4.65"
    ]
}

我需要把它整理出来并得到一个新的对象数组，如下所示：

const second = [
    {
        "apples": "5.78",
        "oranges": "54.25",
        "cucumbers": "97.28",
        "carrots": "6.48"
    },
    {
        "apples": "3.96",
        "oranges": "41.29",
        "cucumbers": "97.13",
        "carrots": "5.1"
    },
    {
        "apples": "3.71",
        "oranges": "33.44",
        "cucumbers": "95.95",
        "carrots": "4.65"
    }
]

非常感谢！！

Answer 1

请确保您首先与我们分享您是如何尝试解决此问题的，以便我们知道您已经尝试过的所有内容。

也就是说，这次我们会帮助你。 您可以使用Object.entries()创建第二个数组：

const first = {
    "apples": [
        "5.78",
        "3.96",
        "3.71"
    ],
    "oranges": [
        "54.25",
        "41.29",
        "33.44"
    ],
    "cucumbers": [
        "97.28",
        "97.13",
        "95.95"
    ],
    "carrots": [
        "6.48",
        "5.1",
        "4.65"
    ]
}

const second = Object.entries(first).reduce((res, [key, arr]) => {
  arr.forEach((val, i) => {
    if (!res[i]) res[i] = {};
    res[i][key] = val;
  });
  return res;
}, []);

console.log(second);

// Output
[
    {
        "apples": "5.78",
        "oranges": "54.25",
        "cucumbers": "97.28",
        "carrots": "6.48"
    },
    {
        "apples": "3.96",
        "oranges": "41.29",
        "cucumbers": "97.13",
        "carrots": "5.1"
    },
    {
        "apples": "3.71",
        "oranges": "33.44",
        "cucumbers": "95.95",
        "carrots": "4.65"
    }
]

Answer 2

 const d = {"apples":["5.78","3.96","3.71"],"oranges":["54.25","41.29","33.44"],"cucumbers":["97.28","97.13","95.95"],"carrots":["6.48","5.1","4.65"]} const r = Object.values(d)[0].map((_,i)=>Object.fromEntries(Object.entries(d).map(([k,v])=>[k,v[i]]))) console.log(r)