如何获取某些元素的文本 BeautifulSoup Python

Question

我有这种 html 代码

<tr>
  <td class="a">...</td>
  <td class="a">...</td>
  <td class="a">
    <p>
      <sup>
        Name Name Name
      </sup>
    </p>
  </td>
  <td class="a">...</td>
  <td class="a">...</td>
  <td class="a">
    <p>
      <sup>25.01.1980</sup>
    </p>
  </td>
  <td class="a">...</td>
  <td class="a">...</td>
</tr>
<tr>...</tr>
<tr>...</tr>

我需要获取每个tr的第 3 个和第 5 个td的文本

显然这不起作用:)

from bs4 import BeautifulSoup
import index

soup = BeautifulSoup(index.index_doc, 'lxml')

for i in soup.find_all('tr')[2:]:
    print(i[2].text, i[4].text)

Answer 1

您可以使用css selectors和伪:nth-of-type()到 select 您的元素（假设您需要日期，所以我选择了第 6 个 td）：

data = [e.get_text(strip=True) for e in soup.select('tr td:nth-of-type(3),tr td:nth-of-type(6)')]

并获取tuples列表：

list(zip(data, data[1:]))

例子

from bs4 import BeautifulSoup

html = '''
<tr>
  <td class="a">...</td>
  <td class="a">...</td>
  <td class="a">
    <p>
      <sup>
        Name Name Name
      </sup>
    </p>
  </td>
  <td class="a">...</td>
  <td class="a">...</td>
  <td class="a">
    <p>
      <sup>25.01.1980</sup>
    </p>
  </td>
  <td class="a">...</td>
  <td class="a">...</td>
</tr>
<tr>...</tr>
<tr>...</tr>
'''
soup = BeautifulSoup(html)

data = [e.get_text(strip=True) for e in soup.select('tr td:nth-of-type(3),tr td:nth-of-type(6)')]

list(zip(data, data[1:]))