How to pass variables into different functions inside a php controller

Question

我正在尝试创建一个表单选择字段，显示所有具有指定类型的学校。 代码的 laravel 功能有效。 因为我在一页上有这个，所以一切正常。 但我被要求将它们移到两个单独的页面上。 我的问题是如何将我的 $type 变量从我的 storeType function 正确地放入我的学校选择 function 中？ 见代码：

public function schoolSelection(School $school,$type)
{
    $schools=$school->where('type','=',$type)->get();
    return view('auth.schoolSelection',compact('schools'));
}

public function storeType(Request $request, School $school)
{
    $data=$request->all();
    $type=$data['schoolType'];

    return redirect()->route('schoolSelection',compact('type'));
}

路线：

Route::get('schoolSelection/type',[RegisteredUserController::class,'schoolType'])->name('schoolType');

Route::get('schoolSelection/school',[RegisteredUserController::class,'schoolSelection'])->name('schoolSelection');

Route::post('schoolSelection/type',[RegisteredUserController::class,'storeType'])->name('type.store');

Route::post('schoolSelection/school',[RegisteredUserController::class,'schoolSelection'])->name('schoolSelection.store');

Answer 1

如果这两个函数都在同一个 controller 中，那么您可以将类型设置为全局变量。

class TestController extends Controller
{
    private $type;

   public function storeType(Request $request, School $school)
{
    $data=$request->all();
    $this->type=$data['schoolType'];

    return redirect()->route('schoolSelection',compact('type'));
}
   public function schoolSelection(School $school)
{
   $type = $this->$type;

    $schools=$school->where('type','=',$type)->get();
    return view('auth.schoolSelection',compact('schools'));
}
}