如何在异步任务之间传递 serial_asyncio

Question

我需要在 2 个异步任务之间从 serial_asyncio 传递读取器和写入器，第一个任务是读取用户键盘输入，当用户按 x 时，function 将信息发送到 Arduino，第二个任务读取来自 Arduino 的响应并为特定响应做一些事情

代码：

import warnings
import serial
import serial.tools.list_ports
import requests
import json
import asyncio
import keyboard
import time
from serial_asyncio import open_serial_connection

with open("config.json") as config:
    cfg = json.load(config)
    config.close()

headers = {'Accept': 'application/json'}

url = f"""https://{cfg["web"]}/login?username={cfg["user"]}&password={cfg["password"]}""" 

get_token = requests.post(url, headers=headers)
token = get_token.json()
my_token = token["token"]

arduino_ports = [
    p.device
    for p in serial.tools.list_ports.comports()
    if p.manufacturer and 'Arduino' in p.manufacturer
]
if not arduino_ports:
    raise IOError("No Arduino found")
if len(arduino_ports) > 1:
    warnings.warn("Multiple arduinos, select first")


async def arduino_listen(cfg, headers, reader):
    print('arduino_listen task created')
    while True:
        await asyncio.sleep(0.1)
        info = await reader.readline()
        print('arduino respond:', info)
        if "good" in str(info):
            print('good from arduino')
        if "bad" in str(info):
            print('bad from arduino')


async def arduino_writer(cfg, headers, writer):
    print('arduino_writer task created')
    keypress = False
    key = 'x'
    while True:
        if keypress and not keyboard.is_pressed(key):
            print('x pressed on keyboard, send 5')
            writer.write(b'5')
            await asyncio.sleep(0.3)
            keypress = False
        elif keyboard.is_pressed(key) and not keypress:
            keypress = True


async def serial():
    print(f'serial task created, arduino port {arduino_ports[0]} selected')
    reader, writer = await open_serial_connection(url=arduino_ports[0], baudrate=115200)

#reader, writer = await open_serial_connection(url=arduino_ports[0], baudrate=115200)

loop = asyncio.get_event_loop()
loop.create_task(serial())
loop.create_task(arduino_listen(cfg, headers, reader))
loop.create_task(arduino_writer(cfg, headers, writer))
loop.run_forever()

我的问题是，如何将连接从串行 function 任务传递到 arduino_listen 和 arduino_writer 任务，我尝试在 loop.create_task 之前添加reader, writer = await open_serial_connection(url=arduino_ports[0], baudrate=115200)但出现意外错误

Answer 1

避免提供与您的模块名称冲突的函数名称，在您的情况下它是关于serial的。 我们称它为start_serial 。
由于start_serial是启动串行连接的初始function arduino_listen和arduino_writer应该在它之后并行运行。
将代码的最后部分更改为以下内容：

async def start_serial():
    print(f'serial task created, arduino port {arduino_ports[0]} selected')
    reader, writer = await open_serial_connection(url=arduino_ports[0], baudrate=115200)
    return reader, writer

async def main():
    reader, writer = await start_serial()
    await asyncio.gather(
        arduino_listen(cfg, headers, reader),
        arduino_writer(cfg, headers, writer))


asyncio.run(main())