如何覆盖异常

Question

我正在编写一个 python / selenium 脚本，用于搜索网站以查找元素，然后最终将这些元素值写入表格。

当它识别出该元素不存在时，它会按预期抛出NoSuchElementException 。

我一直在试图弄清楚如何覆盖此异常，而是用默认值（例如“无值”）填充表。

问题是，python 似乎忽略了我的任何尝试，只是无论如何抛出异常，导致脚本执行在能够填充表之前结束。

有任何想法吗？

file_1.py

def getAttributes(self):
...
...
...
try: 
    score = box.find_element(By.CLASS_NAME, 'dealClass').get_attribute('innerHTML').strip()  
    if not score:
        raise NoSuchElementException(f"Score does not currently exist for {name}, as of {datetime.today()}") 
except NoSuchElementException as e: 
    print('Exception is: ', e)
    # Writing remediating code here but it never seems to work..
    raise
...




file_2.py

def reportResults(self):
...
    searchResults = self.find_element(By.ID, 'search_results_table') 
    report = ReportSearchResults)
    table = PrettyTable(field_names=["Name", "Price", "Score"])
    table.align["Name"] = "l"
    table.align["Price"] = "l"
    table.align["Score"] = "r"
    table.add_rows(report.getAttributes())
    print(table) 
...

Answer 1

当您捕获异常时，您可以通过给score一个值来“修复”它。 那时没有必要重新提出异常； 你已经处理了它，所以让你的脚本继续进行，就好像什么也没发生一样。

def getAttributes(self):

    ...

    try: 
        score = box.find_element(By.CLASS_NAME, 'dealClass').get_attribute('innerHTML').strip()  
        if not score:
            # You're going to catch it, and you don't really need
            # a long message telling you what went wrong. *You* raised
            # this one, and you know why, and you're going to fix it.
            raise NoSuchElementException("no score") 
    except NoSuchElementException as e: 
        score = 'No value'

    ...