MySQL：如何获取count> 1的记录？

Question

我有一个这样的SQL：

SELECT *, count(*) as cc 
FROM manytomany 
GROUP BY aid, bid
ORDER BY cc DESC

返回带有计数＃的所有记录。

但是，如果我只想获得数> 1的那些，我该怎么办？

Answer 1

SELECT *, count(*) as cc 
FROM manytomany 
GROUP BY aid, bid
HAVING 1 < count(*)
ORDER BY cc DESC

Answer 2

您需要一个HAVING子句，例如：

SELECT *, count(*) as cc 
FROM manytomany 
GROUP BY aid, bid
HAVING COUNT(*) > 1
ORDER BY cc DESC

这是一些背景知识 。

Answer 3

您使用having子句。

SELECT *, count(*) as cc
FROM manytomany
GROUP BY aid, bid
HAVING count(*) > 1
ORDER BY cc DESC

Answer 4

SELECT *, count(*) as cc 
FROM manytomany 
GROUP BY aid, bid
HAVING COUNT(*) > 1
ORDER BY cc DESC

我不使用MySQL，但它应该支持HAVING -it已经存在了一段时间。

Answer 5

SELECT *, count(*) as cc 
FROM manytomany 
GROUP BY aid, bid
HAVING cc>1
ORDER BY cc DESC

Answer 6

HAVING子句

   SELECT *, count(*) as cc 
    FROM manytomany 
    GROUP BY aid, bid
    HAVING cc > 1
    ORDER BY cc DESC