SQL-使用联接将列表传递给查找表

Question

我希望能够遍历一个列表并返回所有列表元素均已匹配的一行。

例如

恐怕我的ID列表是1,2,3，我想编写一个SQL语句来执行以下操作（不间断）。

从TBL中选择id1 0 = 0并且id2 = 1 AND id2 = 2 AND id2 = 3

这可能吗？

提前致谢

Answer 1

您是说要所有具有匹配的id2=1和匹配的id2=2以及匹配的id2=3所有id1记录吗？

WITH tbl As
(
SELECT 1 AS id1, 1 AS id2 UNION ALL
SELECT 1 AS id1, 2 AS id2 UNION ALL
SELECT 1 AS id1, 3 AS id2 UNION ALL
SELECT 1 AS id1, 4 AS id2 UNION ALL
SELECT 2 AS id1, 1 AS id2 UNION ALL
SELECT 2 AS id1, 2 AS id2 UNION ALL
SELECT 3 AS id1, 1 AS id2 UNION ALL
SELECT 3 AS id1, 2 AS id2 UNION ALL
SELECT 3 AS id1, 3 AS id2
)
SELECT id1 
FROM tbl 
WHERE id2 IN (1,2,3)
GROUP BY id1
HAVING COUNT(DISTINCT id2) = 3

退货

id1
-----------
1
3

那是你需要的吗？

Answer 2

而且这里没有道理。 您可能想使用OR： id2 = 1 OR id2 = 2 OR id2 = 3甚至更好的IN：

SELECT id1 FROM TBL WHERE id2 IN (1,2,3)

Answer 3

根据问题的标题进行第三次猜测-如果值列表在第二张表中，则可以编写查询以基于对第二张表的联接从第一张表中选择值，如下所示：

SELECT id1 FROM TBL T1
join TBL2 T2 on T1.id2 = T2.id

当然，在此示例中，TBL2在id列中仅必须具有值1、2和3。