
[英]How to get a fully-qualified function name in C++ (gcc), _excluding_ the return type?
[英]How to get the fully qualified path name in C++
是否有一个函数返回任何输入文件的完全限定路径名?
我想的是:
LPCSTR path = "foo.bar"
LPCSTR fullPath = FullyQualifiedPath(path);
//fullPath now equals C:\path\to\foo.bar
谢谢
在Win32中,调用GetFullPathName
函数。
使用boost :: filesystem http://www.boost.org/doc/libs/1_44_0/libs/filesystem/v2/doc/index.htm
#include <iostream>
#include <boost/filesystem.hpp>
int main()
{
boost::filesystem::path p = boost::filesystem::complete("foo.bar");
std::cout << p;
}
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