php数组：如何只打印数组值而不打印键

Question

此代码循环遍历mysql表并打印出空/空字段。 然而，它打印数组值和这样的键

Array ( 
    [0] => Field "dob" on entry "1" is empty/null 
    [1] => Field "user_name" on entry "7" is empty/null
)

如何field "dob" on entry "1" is empty/null打印此field "dob" on entry "1" is empty/null

$sql = "SELECT * FROM userinfo";
$res = mysql_query($sql);
while ($row = mysql_fetch_array($res)) {
    foreach($row as $key => $field) {
        if(empty($field)) {
            $emptyFields[] = sprintf('Field "%s" on entry "%d" is empty/null', $key,   $row['userid']);
         }
     }
}
print_r($emptyFields);

Answer 1

echo implode('<br>', $emptyFields);

Answer 2

那是因为您使用print_r输出该数组。 因此输出的格式对人类可读。 为了使它更漂亮，尝试像之前使用该字段一样迭代它：

foreach($emptyFields as $key => $field) {
echo('Field "'.$field.'" on entry "'.$emptyField['userid'].'" is empty/null');
}

Answer 3

$sql = "SELECT * FROM userinfo";
$res = mysql_query($sql);
while ($row = mysql_fetch_array($res)) {
  foreach($row as $key => $field) {
    if(empty($field)) {
      $emptyFields[] = sprintf('Field "%s" on entry "%d" is empty/null', $key,  $row['userid']);
    }
  }
}

Answer 4

我不知道我是否正确，但我认为你的问题的解决方案是：

将最后一行更改为：

$emptyFields[] = sprintf('Field "%s" on entry "%d" is empty/null', $field, $row['userid']);}}}print_r($emptyFields);