当我定义一个指向 class 的指针时，错误：预期的构造函数、析构函数或类型转换发生在“*”标记之前

Question

int buffer[gSizeOfGrid][gSizeOfGrid];
CList *currentCList;
Grid *currentGrid; //this line get the error
int aroundinfo[4];
//other functions are not revelant maybe? They don't
//use currentGrid.

class 网格具有 header：

class Grid
{
public:
    Grid();
    //create default cList object for the grid .
    Grid(CList*);
    //create cList and bind existing clist object.
    bool rebind(CList*);
    //rebind cList.
    ~Grid();
    void init(int ants,int bugs);
    //init a grid with ants and bugs according to parameter.
    void GetSnapshot();
    //synchronize grid buffer with clist.
    void Step();
    //make the world go on!
    bool spawn(Creature&,Position);
    //create a creature on the grid.
    //if success, return true.
    //if there are already another creature return false.
    void move(Position,int);
    void eat(Position,int);
    void breed(Position,int);
    void destroy(Position);
private:
    CList* theList;
};

Clist Class 看起来一样，但在声明中没问题：

using namespace std;
class CList
{
public:
    CList();
    int CreateObject(Creature&,Position);
    Creature& GetObject(int);
    bool RemoveObject(Position);
    bool RemoveObject(int);
    int getType(Position);
    void cleanup();
    vector<Creature*> list;
    int size();
};

为什么 Grid* 声明出错但 CList* 没问题？ 谢谢！

Answer 1

这是因为class Grid对指针currentGrid不可见。 只需执行以下操作，它应该可以工作；

class Grid;
Grid *currentGrid;

我假设您可能不想在此声明之前#include Grid header，因为Grid本身正在使用CList 。 最好的方法应该是在此声明之前包含所有标题。