从 NSString 的左侧删除空格

Question

我只需要从 NSString 的左侧删除空格我的意思是

如果我有" This is a good day"我将有"This is a good day"

只有左边的空格

请有任何建议

Answer 1

只需使用

NSString* result = [yourString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];

它将从左侧和右侧删除所有多余的空间，但不会从中间删除

并删除空格和\n使用

NSString* result = [yourString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];

Answer 2

使用下面从您的NSString中删除白色和新行字符。

NSString* result = [yourString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];

Answer 3

Nsstring *str="   This is a good day";

  while ([str rangeOfString:@"  "].location != NSNotFound) {
    str = [str stringByReplacingOccurrencesOfString:@"  " withString:@" "];
}

nslog(@"string after removing space %@",)

Answer 4

这是我遇到相同问题时提出的解决方案：

- (NSString*)trimBlankCharactersFromBeginningOfString:(NSString*)originalString
{
    //we are only trimming the characters on the left side of the string
    NSInteger count = [originalString length];
    NSString *trimmedNewText = originalString;
    for (int i = 0; i < count; i++) {
        if([[originalString substringWithRange:NSMakeRange(i, 1)] rangeOfCharacterFromSet:[NSCharacterSet whitespaceCharacterSet]].location == NSNotFound)
        {
            trimmedNewText = [originalString substringFromIndex:i];
            break;
        }
        else
        {
            if(i+1 < count)
            {
                trimmedNewText = [originalString substringFromIndex:i+1];
            }
            //since we are exiting the loop as soon as a non blank space character is found
            //then this is just really checking to see if we are on the last character of an
            //all whitespace string. can't say i+1 here because that would give an index out
            //of bound exception
            else
            {
                trimmedNewText = @"";
            }
        }
    }
    return trimmedNewText;
}

Answer 5

对于仅向左修剪的解决方案是在字符串的右侧添加一个虚拟字符，修剪字符串，然后将其删除。

NSString* tempString = [NSString stringWithFormat@"%@T", yourString];
NSString* result = [yourString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
return [result substringToIndex:[result length]-1];

Answer 6

只有左边的空格

while ([[yourString substringToIndex:1] isEqualToString:@" "])
    yourString = [yourString substringFromIndex:1];

Answer 7

NSString *str = @" This is a good day";    
NSArray *arrString = [str componentsSeparatedByString:@"T"];
NSString *strSpace = [arrString objectAtIndex:0];   // White space
NSString *strString = [arrString objectAtIndex:1];   //This is a good day  

然后，您可以将字符串中的 append T作为

NSString *strT = @"T";
strString = [strT stringByAppendingString:strString];