PHP 第一个活动按钮

Question

我有一个小问题要问你！

我从 mysql 我的按钮中进行选择，例如：

$query = mysql_query("select * from navigation");

while ($row = mysql_fetch_assoc($query)) {

    echo '<a href="?id=$row['id']">$row['name']</a>';

}

so I call all the navigation from mysql and I have a class in css which is called as.active, this class make a active button when I click it, but how can I make the first button active?

$query = mysql_query("select * from navigation");

while ($row = mysql_fetch_assoc($query)) {

     if ($row['id'] == $_GET['id'])) {
         echo '<a class="active" href="?id=$row['id']">$row['name']</a>';
     } else {
         echo '<a href="?id=$row['id']">$row['name']</a>';
     }

}

Answer 1

尝试这个。

<?PHP
$query = mysql_query("select * from navigation");
$first = true;
while($row = mysql_fetch_assoc($query)) {
    if ((!array_key_exists('id', $_GET) && $first) || $row['id'] == $_GET['id']) {
         $extra = 'class="active"';
         $first = false;
    } else
         $extra = '';

    echo "<a $extra href=\"?id={$row['id']}\">{$row['name']}</a>";
}
?>