r使用do.call（rbind）或ddply合并tapply的结果

Question

我有日期/时间信息，我想获取按年份分组的“季节”中日期的平均，最小，最大，范围，而我取得成功的唯一方法就是轻按。 最接近的是tapply中的汇总功能。 结果是我仅假设的是最小，最大，第一曲线，中位数等年份的列表。这些并不是我真正需要的，但效果很好。

我从1个赛季的Tapply函数获得的结果示例：

$`2003`
                     Min.                   1st Qu.                    Median                      Mean                   3rd Qu.                      Max. 
"2003-04-22 00:00:00 UTC" "2003-05-03 00:00:00 UTC" "2003-05-12 00:00:00 UTC" "2003-05-10 02:00:00 UTC" "2003-05-18 00:00:00 UTC" "2003-05-21 00:00:00 UTC" 

$`2004`
                     Min.                   1st Qu.                    Median                      Mean                   3rd Qu.                      Max. 
"2004-04-07 00:00:00 UTC" "2004-04-13 00:00:00 UTC" "2004-05-10 00:00:00 UTC" "2004-05-01 07:08:56 UTC" "2004-05-11 12:00:00 UTC" "2004-05-20 00:00:00 UTC" 

我想要做的是将我在不同季节生成的这些列表合并到一个很大的快乐数据框中，然后将其导出到csv中。 我搜寻了，并且变得更加困惑。 大多数人认为最简单的是

test = do.call(rbind, sSM, eSM, sC) #note here sSM, eSM, sC are my "seasons"

但是，这给了我一个错误消息或空的“测试”框架。

我已经阅读了plyr软件包，并假定ddply而不是tapply可以将结果强制进入数据帧，但是我无法弄清楚如何使它工作，因为我无法让它完成我的功能将需要诸如平均值，最小值，最大值和范围...

我想要的最终结果是这样的：

Season   Year   Min           Max      Mean        Median  
sSM     2003   2003-04-21   2003-5-1  2003-4-25   2003-4-23
eSM     2003...
sSM     2004...
eSM     2004...

然后，我想做完全一样的事情，只是跨年确定。 我有一个ID字段，几年来对同一个人进行了测量。 我想为每个季节的几年中该人提供一个平均的开始日期。 排除那些没有被多年测量的人。

由于我不了解如何操作列表和数组，甚至不知道tapply在做什么，所以我对如何解决所有这些都感到困惑。 我是否创建一个空的数据框并将所有这些内容放入某个循环中？ 下面是几年中四个“季节”中的一些示例数据，请注意，某些日期带有日期和时间戳，而有些只是带有日期。

    structure(list(Year = c(2003L, 2003L, 2003L, 2003L, 2003L, 2003L, 
2003L, 2004L, 2004L, 2004L, 2004L, 2004L, 2004L, 2005L, 2005L, 
2005L, 2005L, 2005L, 2005L, 2006L, 2006L, 2006L, 2006L), ID = structure(c(11L, 
12L, 13L, 14L, 15L, 16L, 17L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 
9L, 10L, 14L, 15L, 1L, 2L, 3L, 6L), .Label = c("c_002", "c_102", 
"c_104", "c_105", "c_109", "c_401", "c_9814", "c_9815", "c_9816", 
"c_9819", "c_9901", "c_9902", "c_9905", "c_9908", "c_9911", "c_9912", 
"c_9916"), class = "factor"), sSM = structure(c(10L, 10L, 9L, 
17L, 8L, 8L, 7L, 18L, NA, 1L, NA, 15L, 13L, 12L, 6L, 3L, 5L, 
2L, 4L, 16L, 14L, 11L, 11L), .Label = c("04/07/2004 15:00", "04/23/2005 10:01", 
"04/25/2005 03:01", "04/27/2005 02:00", "04/27/2005 08:00", "04/29/2005 04:00", 
"05/01/2003", "05/03/2003", "05/04/2003", "05/05/2003", "05/05/2006", 
"05/07/2005 16:01", "05/11/2004 11:00", "05/11/2006", "05/13/2004 08:00", 
"05/14/2006", "05/17/2003", "05/17/2004 12:02"), class = "factor"), 
    eSM = structure(c(13L, 18L, 15L, 21L, 16L, 10L, 14L, 20L, 
    NA, 1L, NA, 11L, 7L, 5L, 6L, 17L, 3L, 2L, 4L, 19L, 9L, 12L, 
    8L), .Label = c("04/27/2004 05:00", "05/01/2005 05:00", "05/06/2005 05:00", 
    "05/08/2005 07:01", "05/12/2005 21:00", "05/15/2005 19:00", 
    "05/18/2004 13:00", "05/18/2006", "05/20/2006", "05/21/2003", 
    "05/21/2004 01:01", "05/23/2006", "05/24/2003", "05/25/2003", 
    "05/26/2003", "05/27/2003", "05/27/2005 01:00", "05/28/2003", 
    "05/28/2006", "06/01/2004 02:01", "06/03/2003"), class = "factor"), 
    sC = structure(c(9L, 12L, 16L, 19L, 18L, 12L, 7L, 13L, NA, 
    10L, NA, 20L, 4L, 14L, 11L, 5L, 1L, 2L, 3L, 8L, 17L, 6L, 
    15L), .Label = c("05/26/2005 00:00", "05/26/2005 10:00", 
    "05/27/2005 06:01", "05/28/2004 08:00", "05/29/2005 23:01", 
    "05/29/2006", "05/30/2003", "05/30/2006", "05/31/2003", "05/31/2004 06:01", 
    "05/31/2005 15:00", "06/01/2003", "06/01/2004 07:02", "06/01/2005 16:00", 
    "06/01/2006", "06/03/2003", "06/03/2006", "06/04/2003", "06/05/2003", 
    "06/05/2004 01:00"), class = "factor"), eC = structure(c(11L, 
    2L, 15L, 6L, 17L, 17L, 2L, 8L, NA, 7L, NA, 13L, 5L, 9L, 9L, 
    3L, 10L, 1L, 4L, 12L, 14L, 16L, 12L), .Label = c("06/03/2005 18:00", 
    "06/04/2003", "06/04/2005 04:01", "06/05/2005 05:01", "06/06/2004 22:00", 
    "06/07/2003", "06/07/2004 23:00", "06/08/2004 19:01", "06/08/2005 03:00", 
    "06/10/2005 20:00", "06/12/2003", "06/13/2006", "06/14/2004 00:00", 
    "06/14/2006", "06/16/2003", "06/18/2006", "06/19/2003"), class = "factor")), .Names = c("Year", 
"ID", "sSM", "eSM", "sC", "eC"), class = "data.frame", row.names = c(NA, 
-23L))

这是我到目前为止编写的一些代码：

dates$StartSM =  as.POSIXct(strptime(dates$sSM,"%m/%d/%Y",tz="UTC"),tz="UTC")                 
dates$EndSM =  as.POSIXct(strptime(dates$eSM,"%m/%d/%Y",tz="UTC"),tz="UTC")
dates$EndC =  as.POSIXct(strptime(dates$eC,"%m/%d/%Y %H:%M",tz="UTC"),tz="UTC")
dates$StartC =  as.POSIXct(strptime(dates$sC,"%m/%d/%Y %H:%M",tz="UTC"),tz="UTC")
sSpringM = tapply(dates$StartSM, dates$Year, summary)
eSpringM  = tapply(dates$EndSM, dates$Year, summary)
sCalving = as.vector(tapply(dates$StartC, dates$Year, summary))
eCalving = tapply(dates$EndC, dates$Year, summary)
datadates = do.call(rbind, sSpringM, eSpringM, sCalving)

Answer 1

您（无论如何都在顶部）有一个列表，将其称为“您的列表”。 尝试打印这些：

lapply(yourlist, format, "%Y-%m-%d")

如果要将它们放在矩阵中：

do.call(rbind, sapply(yourlist, unlist))

我在您的结构中看不到任何“冬天”，“春天”等。 过去，我使用data.table包的年，季，月和周函数返回年，季，月和周的数值向量。 使用整数年加上适当的分数加法（例如year（。）+ quarter / 4）进行绘制很容易。 比相应的切割和标签麻烦要容易的多。