javascript中的拖放操作

Question

我知道如何在JavaScript中实现拖放效果，但我发现在某些站点中，拖放操作的速度会导致不同的结果。

以谷歌地图为例，地图视图是可拖动的，当您慢慢拖动地图时，地图将随您的鼠标移动，但是如果您快速拖动地图然后放下鼠标，地图将继续移动（限制距离），似乎它有一个缓冲距离。

我想知道如何制作它？

Answer 1

不幸的是，没有香草效果。

您将需要计算各种参数，例如完成拖动所需的距离，方向和时间。

然后根据结果，您可以计算贝塞尔曲线并扩展动画，使其看起来无缝平滑。

这是一个例子...... http://jsfiddle.net/an44z/

它可以工作，如果可能不是那么好（匆忙写一个旧项目，但它可能会让你很好地了解正在发生的事情 - 应该发生）。

编辑：或者你可以研究这个mooTools的例子，因为它几乎就是你所追求的。 http://mootools.net/demos/?demo=Drag.Scroll

Answer 2

听起来你正在寻找某种“拖动速度”。 我今天早上花了一些时间把这个鼠标抛到一起的例子给你，所以我希望它有所帮助（我也有一些乐趣）。 *原则*对于您想要做的事情是相同的，并且您可以享受很多乐趣。

使用Javascript的Brunt：

// this is the easing I used in my "throwing" animation
// I use this to average out some of the arrays (distance & angle)
$.easing.easeOutCirc = function (x, t, b, c, d) {
    return c * Math.sqrt(1 - (t=t/d-1)*t) + b;
}

// stores the last drag spot, useful for calculating distances between points
var drag_last_spot;
// stores distances for use with calculating animation distance
var drag_distances;
// stores rads for use with calculating throw angle
var drag_rads;
// keeps the offset of the initial click to know where the mouse "went down" on the box
var drag_offset;
// keeps track of the "current target" since mouseUp and MouseMove are document level
var drag_target;
// keeps track of how long you held your mouse down on the box (to determine animation length)
var drag_time;

// taken via Google from http://jsfromhell.com/array/average
average = function(a){
    var r = {mean: 0, variance: 0, deviation: 0}, t = a.length;
    for(var m, s = 0, l = t; l--; s += a[l]);
    for(m = r.mean = s / t, l = t, s = 0; l--; s += Math.pow(a[l] - m, 2));
    return r.deviation = Math.sqrt(r.variance = s / t), r;
}
function onMouseDown(event) {
    // offset and last_spot are the same for the first move iteration
    drag_time = (new Date).getTime();
    drag_offset = drag_last_spot = {
        x: event.offsetX,
        y: event.offsetY
    };

    // initialize or reset the distances and angle arrays
    drag_distances = [];
    drag_rads = [];

    // because there are multiple boxes, we need to keep track of the target since our events are document level
    drag_target = $(this);

    $(document).bind("mousemove", onMouseMove);
    $(document).bind("mouseup", onMouseUp);
}

function onMouseMove(event) {
    // use pathagorean theorem for distance between two points (yay geometry!)
    var dist = Math.sqrt(Math.pow(drag_last_spot.x - event.clientX, 2) + Math.pow(drag_last_spot.y - event.clientY, 2));

    // push all the distances to this array for later use
    drag_distances.push(dist);

    // push all radians to this array for later use
    var cur_rad = Math.atan2(event.clientY - drag_last_spot.y, event.clientX - drag_last_spot.x);
    drag_rads.push(cur_rad);

    // we need to know the last drag spot so we can calc the distance of the points during the next onMouseMove
    drag_last_spot = {
        x: event.clientX,
        y: event.clientY
    };

    drag_target.css({left:event.clientX - drag_offset.x, top:event.clientY - drag_offset.y});
}

function onMouseUp(event) {
    /* FYI wherever you see .slice(-N) you can change N to any number. I recommend a small number as a short drag will only have 5 or 10 items. A big number will average more of your "throw", but a small number is seemingly safer.*/

    // this is the total duration of how long you dragged for
    var duration = ((new Date).getTime() - drag_time);

    // this is the distance of your drag (I times by three for a better animated effect)
    var dist = average(drag_distances.slice(-3)).mean * 3;

    // these help determine the direction of your throw (figures out the angle)
    var rad = average(drag_rads.slice(-3)).mean - Math.PI / 2;
    var to_left = event.clientX + Math.sin(rad) * -dist - drag_offset.x;
    var to_top = event.clientY + Math.cos(rad) * dist - drag_offset.y;

    // now to animation your throw!
    drag_target.animate({left:to_left, top:to_top}, duration * 2, "easeOutCirc");

    $(document).unbind("mousemove");
    $(document).unbind("mouseup");
}

这个例子只是冰山一角，所以我说要乱用脚本来了解它是如何工作的，因为你可能会想出新的很酷的方法来做事。 祝好运！