我有3张桌子。
Mark
id_mark
mark_name
example record:
1, 'Ford'
2, 'Fiat'
Model
id_model
id_mark
mondel_name
example record:
1, 1, 'Focus'
2, 2, 'Panda'
Adds
id_adds
id_model
name
price
etc.
example records:
1 1 'My ad', 20000
2 1 'My ad2', 30000
3 2 'My ad3', 30000
如何执行返回结果的查询（“标记添加计数”）示例：
Ford 2
Fiat 1
2 and 1 count
您将需要两个联接。 我已将第二个指定为LEFT OUTER JOIN这样对于没有关联广告的品牌，它可能会返回0。 Mark通过Model加入Adds 。
SELECT
mark_name,
COUNT(id_adds) AS num_ads
FROM
Mark JOIN Model ON Mark.id_mark = Model.id_mark
LEFT OUTER JOIN Adds ON Model.id_model = Adds.id_model
GROUP BY mark_name
SELECT
mark_name,
COUNT(id_adds) AS num_adds
FROM Mark
LEFT JOIN Model ON Mark.id_mark = Model.id_mark
LEFT JOIN Adds ON Model.id_model = Adds.id_model
GROUP BY Mark.id_mark
Select mark.mark_name, count(adds.id_adds) from adds join model on adds.id_model = model.id_model join mark on model.id_mark = mark.id_mark group by mark.id_mark;
我不是100％确信，但是类似的东西应该可以工作