上传到服务器后需要一些帮助才能解决php脚本[重复]

Question

可能重复：
警告：mysql_fetch_ *期望参数1是资源，布尔给定错误

我在家里使用xampp ......我需要在下周在学校展示我的工作，因此我决定上传到免费托管服务器。 在我的xampp机器上它工作得非常好，但是一旦我将数据库和我的文件上传到public_html ，文件就再也无法正常工作了。

我的网站

这是登录页面，但在我使用准确的用户名和密码登录后，出现了一些错误，例如

Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in /home/hubertj/public_html/login_now.php on line 41

Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in /home/hubertj/public_html/login_now.php on line 43

Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in /home/hubertj/public_html/login_now.php on line 51

Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in /home/hubertj/public_html/login_now.php on line 59

Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in /home/hubertj/public_html/login_now.php on line 67

Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in /home/hubertj/public_html/login_now.php on line 75

Warning: Cannot modify header information - headers already sent by (output started at /home/hubertj/public_html/login_now.php:41) in /home/hubertj/public_html/login_now.php on line 86

但是在我的xampp机器上运行顺利。 因此，我所做的是我在sql界面中尝试了查询，它也可以正常工作。 我无法理解上传到服务器时我错过了什么步骤。 这是我第一次上传带有数据库的网站。 非常感谢。

发生错误的login_now.php代码：

<?php session_start(); ?>
<?php include("Connections/database.php");?>
<?php

$myeid = $_POST['logineid'];
$mypassword = $_POST['password'];

$conn = dbConnect(); //get connected to database    
//successful?
if (!$conn)
    die("Couldn't connect to MySQL");

$query = "select * from emp where EID = '$myeid' and PASS = '$mypassword'";

//run the query
$result = mysql_query($query, $conn);
$row = mysql_fetch_assoc($result);

if (mysql_num_rows($result) > 0 and $row['POSITION']=="manager")    //found a record whose position is manager?
{
    $_SESSION['eid'] = $myeid;  //remember name as a session variable
    $_SESSION['password'] = $mypassword;    //remember password as a session variable
    $_SESSION['start'] = time();    // taking now logged in time
    $_SESSION['expire'] = $_SESSION['start'] + (60 * 60) ;  // ending a session in 60 minutes from the starting time
    header('Location: manager/welmanager.php');     //redirect user to index
}
elseif (mysql_num_rows($result) > 0 and $row['POSITION']=="staff")         //found a record whose position is staff?
{
    $_SESSION['eid'] = $myeid;  
    $_SESSION['password'] = $mypassword;    
    $_SESSION['start'] = time(); 
    $_SESSION['expire'] = $_SESSION['start'] + (60 * 60) ; 
    header('Location: staff/welstaff.php');             //redirect user to index
}
elseif (mysql_num_rows($result) > 0 and $row['POSITION']=="nurse")          
{
    $_SESSION['eid'] = $myeid;      
    $_SESSION['password'] = $mypassword;    
    $_SESSION['start'] = time();
    $_SESSION['expire'] = $_SESSION['start'] + (60 * 60) ; 
    header('Location: nurse/welnurse.php');             //redirect user to index
}
elseif (mysql_num_rows($result) > 0 and $row['POSITION']=="train")          
{
    $_SESSION['eid'] = $myeid;      
    $_SESSION['password'] = $mypassword;    
    $_SESSION['start'] = time(); 
    $_SESSION['expire'] = $_SESSION['start'] + (60 * 60) ; 
    header('Location: train/weltrain.php');             //redirect user to index
}
elseif (mysql_num_rows($result) > 0 and $row['POSITION']=="hr")             
{
    $_SESSION['eid'] = $myeid;      
    $_SESSION['password'] = $mypassword;    
    $_SESSION['start'] = time(); 
    $_SESSION['expire'] = $_SESSION['start'] + (60 * 60) ; 
    header('Location: hr/welhr.php');           //redirect user to index
}
else
{
    $_SESSION['form_error'] = "Invalid Employee ID or Password";
    header('Location: login.php');          //kick back to login
}

dbDisconnect($conn);
?>

我无法弄清楚上传到服务器时错过的步骤。 希望可以有人帮帮我。 谢谢。

我的数据库脚本在这里：

<?php

function dbConnect()
{
    $host = "mysql16.000webhost.com";       //location of MySQL server
    $username = "a5523583_root";        //username to access MySQL Server
    $password = "cailing8195";      //password to access MySQL Server
    $database = "a5523583_jlr";     //database to access

    //try to get connected
    $conn = mysql_connect ($host, $username, $password);

    //try to wselect the database
    $select = mysql_select_db ($database, $conn);
    return $conn;
}

function dbDisconnect($conn)
{
    mysql_close($conn); //get disconnected from DB
}
?>

Answer 1

警告：mysql_fetch_assoc（）期望参数1是资源，在第41行的/home/hubertj/public_html/login_now.php中给出布尔值

这意味着查询返回false，因此您无法使用mysql_fetch_assoc。

您确定要正确连接到数据库吗？ 表存在吗？ 数据库名称是否正确？

Answer 2

调试dbConnect() ，您可以添加

if (!is_resource($conn))
    die("Couldn't connect to MySQL");

然后mysql_error()来获取错误。 我想你在连接时可能会错过mysql_select_db()