谷歌地图API v3放置搜索 - 将另一个参数传递给回调函数

Question

我使用谷歌地图放置API v3来返回许多“类型”的地方，每个地点都由地图上的不同标记表示。

我创建了一个google.maps.places.PlacesService对象，然后按地点类型调用“搜索”方法一次。 每次，我使用不同的回调函数（“搜索”的第二个参数），因为我需要为每种类型选择不同的MarkerImage。

var address = "97-99 Bathurst Street, Sydney, 2000";
geocoder.geocode({ 'address': address }, function (results, status) {
    if (status == google.maps.GeocoderStatus.OK) {
        var location = results[0].geometry.location;

        map.setCenter(location);

        var marker = new google.maps.Marker({
            map: map,
            position: location
        });

        infowindow = new google.maps.InfoWindow();
        var service = new google.maps.places.PlacesService(map);

        // banks
        var req_bank = { location: location, radius: 500, types: ['bank'] };
        service.search(req_bank, banks);

        // bars
        var req_bar = { location: location, radius: 500, types: ['bar'] };
        service.search(req_bar, bars);

        // car parks
        var req_parking = { location: location, radius: 500, types: ['parking'] };
        service.search(req_parking, carparks);

    } else {
        alert("Geocode was not successful for the following reason: " + status);
    }
});

以下是回调函数，它们仅由MarkerImage区分：

function banks(results, status) {
    if (status == google.maps.places.PlacesServiceStatus.OK) {
        for (var i = 0; i < results.length; i++) {
            createMarker(results[i], new google.maps.MarkerImage("/images/bank.png", null, null));
        }
    }
}
function bars(results, status) {
    if (status == google.maps.places.PlacesServiceStatus.OK) {
        for (var i = 0; i < results.length; i++) {
            createMarker(results[i], new google.maps.MarkerImage("/images/bar.png", null, null));
        }
    }
}
function carparks(results, status) {
    if (status == google.maps.places.PlacesServiceStatus.OK) {
        for (var i = 0; i < results.length; i++) {
            createMarker(results[i], new google.maps.MarkerImage("/images/parking.png", null, null));
        }
    }
}

这段代码100％工作，但我想避免重复每个不同地方类型的回调（大约10个）。 有什么办法可以将标记URL传递给回调函数吗？ 然后我只需要一个回调......

Answer 1

以下内容如何：

service.search(req_bank, function (results, status) {
  locations(results, status, "bank");
});

function locations(results, status, type) {
  if (status == google.maps.places.PlacesServiceStatus.OK) {
    // check the type to determine the marker, or pass a url to the marker icon
  }
}