PHP从while循环中获取变量

Question

在我的PHP脚本中，我做了一个mysql_query：

  $full_alarm_sql = "
          SELECT alarms.id, alarms.date, clients.name, clients.number, alarms.controller, alarmstype.type, 
          alarms.alarmstatus, alarms.starttime, alarms.endtime, DATEDIFF(CURDATE(), alarms.date) AS difference
          FROM alarms
          LEFT JOIN clients ON alarms.clientid = clients.id
          LEFT JOIN alarmstype ON alarms.typeid = alarmstype.id
          WHERE DATEDIFF(CURDATE(), alarms.date) <=" . $type . " AND clients.number = " . $market;
  $full_alarm_query = mysql_query($full_alarm_sql);

然后我在获取查询的表中进行while循环：

while ($full_alarm_fetch = mysql_fetch_array($full_alarm_query)) {
  $content .=
    "
           <tr>
          <td>" . $full_alarm_fetch['date'] . "</td>
          <td>" . $full_alarm_fetch['number'] . " | " . $full_alarm_fetch['name'] . "</td>
          <td>" . $full_alarm_fetch['controller'] . "</td>
          <td>" . $full_alarm_fetch['type'] . "</td>
          <td>" . $full_alarm_fetch['alarmstatus'] . "</td>
          <td>" . $full_alarm_fetch['starttime'] . "</td>
          <td>" . $full_alarm_fetch['endtime'] . "</td>
        </tr>";
   $client_name = $full_alarm_fetch['name'] . ' | ' . $full_alarm_fetch['number'];
}

然后我需要使用

$full_alarm_fetch['name'] . ' | ' . $full_alarm_fetch['number'];

所以我现在做的方法似乎并不是最好的方法，这意味着while循环中的变量一次又一次地被覆盖，直到循环终止，然后我才能使用获取信息。

我想知道是否有更好/有效的方式来做我想做的事情。

提前致谢。

Answer 1

您的代码很好。 您可以一次抓取所有rs，然后循环播放，

while ($rs[] = mysql_fetch..);
//done..
for($i=0;$i<sizeof($rs);$i++) or
foreach($rs as $rec)

提供以下好处：

• 将rs缓存在php（序列化数据）中
• 在rs中向后跳

Answer 2

是的，有更好的方法。 您可以先声明一个数组，然后将获取的内容保存在那里，然后遍历该数组。 像这样。

 $fetched_arr = array();
while ($full_alarm_fetch = mysql_fetch_array($full_alarm_query)) {
  $fetched_arr[] = $full_alarm_fetch;
}

然后你循环数组

foreach($fetched_array as $something)
 {
    //here you can save the values in the $content
    // you can use $somethin['date'] and etc.. 
 }